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3 years ago

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Which statement is true about the given expression? A. The "11" in the second term is a constant. B. The "4" in the third term i

s a factor. C. The "3" in the first term is an exponent. D. The "2" in the second term is a coefficient.

2 answers:

lyudmila [28]3 years ago

7 0

Answer:

a

Step-by-step explanation:

Mazyrski [523]3 years ago

3 0

please provide expression. I have no idea.

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use the ruler provided to measure the base of the parallelogram shown to the nearest 0.5 CM which measurement is the closest to

valkas [14]

Answer:

Area of the parallelogram = 21.6 cm²

Step-by-step explanation:

Area of a parallelogram = Base × Height of the side parallel to the base

By using ruler,

Base = 4.8 cm

Height of parallelogram = 4.5 cm

Area of the parallelogram = 4.8 × 4.5

= 21.6 cm²

3 0

3 years ago

Help help help thanks

bija089 [108]

The answers are C and E,
According to the interior and exterior angle theorem, this should be correct:
<3+<4+<6=180
<3+<1=180
<4+<6=<1
so they are the interior opposite of <1

7 0

3 years ago

How is the graph of y=4(2)^x+3 translated from the graph of y=4(2)^x

Pie

Answer:

Vertical movement: Move up 3 units

or

Horizontal movement: Move left 3 units

Step-by-step explanation:

If your parent equation is $f(x) = 4(2)^{x}$ and your child equation is $f(x) = 4(2)^{x} + 3$ , then it has vertically moved up 3 units.

If your parent equation is $f(x) = 4(2)^{x}$ and your child equation is $f(x) = 4(2)^{x+3}$ , then it has moved horizontally left 3 units.

7 0

3 years ago

Read 2 more answers

A vet weighs two puppies. The small puppy weighs 4 2/3 pounds. The large puppy weighs 4 2/3 times as much as the small puppy. Ho

Maksim231197 [3]

4 2/3 lbs = small puppy weight
4 2/3 times the small puppies weight = large puppy weight
4 2/3 × 4 2/3 or 4 2/3^2 = 21.77777.... or in mixed number is 21 7/9 lbs

4 0

3 years ago

A college requires applicants to have an ACT score in the top 12% of all test scores. The ACT scores are normally distributed, w

DochEvi [55]

Answer:

a) The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b) 156 would be expected to have a test score that would meet the colleges requirement

c) The lowest score that would meet the colleges requirement would be decreased to 26.388.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 21.5, \sigma = 4.7$

a. Find the lowest test score that a student could get and still meet the colleges requirement.

This is the value of X when Z has a pvalue of 1 - 0.12 = 0.88. So it is X when Z = 1.175.

$Z = \frac{X - \mu}{\sigma}$

$1.175 = \frac{X - 21.5}{4.7}$

$X - 21.5 = 1.175*4.7$

$X = 27.0225$

The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b. If 1300 students are randomly selected, how many would be expected to have a test score that would meet the colleges requirement?

Top 12%, so 12% of them.

0.12*1300 = 156

156 would be expected to have a test score that would meet the colleges requirement

c. How does the answer to part (a) change if the college decided to accept the top 15% of all test scores?

It would decrease to the value of X when Z has a pvalue of 1-0.15 = 0.85. So X when Z = 1.04.

$Z = \frac{X - \mu}{\sigma}$

$1.04 = \frac{X - 21.5}{4.7}$

$X - 21.5 = 1.04*4.7$

$X = 26.388$

The lowest score that would meet the colleges requirement would be decreased to 26.388.

6 0

3 years ago