Answer:
84 is the highest possible course average
Step-by-step explanation:
Total number of examinations = 5
Average = sum of scores in each examination/total number of examinations
Let the score for the last examination be x.
Average = (66+78+94+83+x)/5 = y
5y = 321+x
x = 5y -321
If y = 6, x = 5×6 -321 =-291.the student cannot score -291
If y = 80, x = 5×80 -321 =79.he can still score higher
If If y = 84, x = 5×84 -321 =99.This would be the highest possible course average after the last examination.
If y= 100
The average cannot be 100 as student cannot score 179(maximum score is 100)
Answer:
32
Step-by-step explanation:
1,024 will be a perfect square if it is the product of 2 of the same numbers:
Calculate the square root of 1024:
= 32
So, the number is 32
To prove that jill is wrong we just need an example of this;
2*3*5*7*11*13 = 30030 (this is the smallest number with 6 different prime numbers)
5953*5981*5987 = 2.13x10^11 (which is obviously a much bigger number)
this is enough to prove that jill is wrong
After 4 years, the account gains $325.8, so 4 years
Answer:
y = -1/2x - 3
Step-by-step explanation:
slope: (y2-y1) / (x2-x1)
(-5 - -2) / (4 - -2)
(-5 + 2) / (4 + 2)
-3 / 6
- 1 / 2
y-intercept: y = mx + b
-5 = -1/2(4) + b
-5 = -2 + b
-3 = b
