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SOVA2 [1]
3 years ago
10

There are 30 students on the school's student council. A special homecoming dance committee is to be formed by randomly selectin

g 6 students from student council. How many possible committees can be formed?
Mathematics
1 answer:
Ghella [55]3 years ago
7 0

Answer:

5 possible committees can be formed. Hope this helps.

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Does anyone know the answers to this algebra question? Will give brainiest
MaRussiya [10]
Option 1 : -22

using formula

(a + b )(a - b ) = a^2 - b^2

(√10 + 2√8) (√10 - 2√8)

= (√10)^2 - (2√8)^2

= 10 - 2×2×8=10-32

= -22

2nd question answer is option 3
3 0
3 years ago
Martin bought a flower vase from a florist. The box in which the vase was packed was shaped like a rectangular prism.
34kurt

Answer:

the answer is C: 1932 sq. cm

Step-by-step explanation:

You want to break down the sections (which is double for each)

there are 6 rectangles but you will only need to calculate for 3

1st rectangle

a = (25) (12)

a = 300 sq. cm

**then multiply by 2 = 600 sq. cm**

2nd rectangle

a = (12) (18)

a = 216 sq. cm

then 216 * 2 = 432 sq. cm

3rd rectangle

a = (25) (18)

a = 450 sq. cm

then 450 * 2 = 900 sq. cm

Total Surface Area

SA = 600 sq. cm + 432 sq. cm + 900 sq. cm

SA = 1932 sq. cm

8 0
3 years ago
The table below shows the number of school absences each day.
lidiya [134]

Answer:

A

Step-by-step explanation:

did it on edge soo there ya go

7 0
4 years ago
Read 2 more answers
Identify the GCF for he given set 23 and 115 A. 1 B. 23 C. 11
s344n2d4d5 [400]

Answer:

b. 23

Step-by-step explanation:

Using factor trees

23                              115

∧                                 ∧

1  23                           5  23

So,

23= 23

115= 23

If you circle the common factors in each factor tree, you get 23.

Therefore your answer is B

3 0
3 years ago
Read 2 more answers
Find the derivative of f(x) = x/6 at x = -2.
AfilCa [17]
f'(x_0)=\lim\limits_{x\to x_0}\dfrac{f(x)-f(x_0)}{x-x_0}\\\\f(x)=\dfrac{x}{6};\ x_0=-2\\\\subtitute\\\\f'(-2)=\lim\limits_{x\to-2}\dfrac{\frac{x}{6}-\frac{-2}{6}}{x-(-2)}=\lim\limits_{x\to-2}\dfrac{\frac{x}{6}+\frac{2}{6}}{x+2}=\lim\limits_{x\to-2}\dfrac{\frac{x+2}{6}}{x+2}\\\\=\lim\limits_{x\to-2}\left(\dfrac{x+2}{6}\cdot\dfrac{1}{x+2}\right)=\lim\limits_{x\to-2}\dfrac{1}{6}=\dfrac{1}{6}
6 0
3 years ago
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