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Iteru [2.4K]
3 years ago
5

Find the derivative of f(x) = x/6 at x = -2.

Mathematics
1 answer:
AfilCa [17]3 years ago
6 0
f'(x_0)=\lim\limits_{x\to x_0}\dfrac{f(x)-f(x_0)}{x-x_0}\\\\f(x)=\dfrac{x}{6};\ x_0=-2\\\\subtitute\\\\f'(-2)=\lim\limits_{x\to-2}\dfrac{\frac{x}{6}-\frac{-2}{6}}{x-(-2)}=\lim\limits_{x\to-2}\dfrac{\frac{x}{6}+\frac{2}{6}}{x+2}=\lim\limits_{x\to-2}\dfrac{\frac{x+2}{6}}{x+2}\\\\=\lim\limits_{x\to-2}\left(\dfrac{x+2}{6}\cdot\dfrac{1}{x+2}\right)=\lim\limits_{x\to-2}\dfrac{1}{6}=\dfrac{1}{6}
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cupoosta [38]

Answer:

<em>The value of the expression for x=3 is 51</em>

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To evaluate a given expression, we simply substitute the value of the variables and complete the operations.

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3 years ago
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3 years ago
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VashaNatasha [74]

Answer:

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The quadratic function can be expressed in the following form:

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Substitute in the general formula above:

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Or, equivalently

\boxed{y=4x^2-8x-4}

5 0
4 years ago
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