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Answer:
-256 +64 - 16 + 4 - 1
Step-by-step explanation:
A series is the summation of all the terms in a sequence.
So it is only the last three options that qualify to be a series.
The series 2 +5 + 8 + 11 + 14 + 17 has no common ratio. It is not geometric.
The series 1+1+2+3+5+ 8 +13 +21 also has no common ratio. It is not geometric.
The series -256 +64 - 16 + 4 - 1 has a common ratio of
There the only series that is geometric is.
-256 +64 - 16 + 4 - 1
Answer:
The vertex Q' is at (4,5)
Step-by-step explanation:
Given:
Quadrilateral PQRS undergoes a transformation to form a quadrilateral P'Q'R'S' such that the vertex point P(-5,-3) is transformed to P'(5,3).
Vertex point Q(-4,-5)
To find vertex Q'.
Solution:
Form the given transformation occuring the statement in standard form can be given as:
The above transformation signifies the point reflection in the origin.
For the point P, the statement is:
So, for point Q, the transformation would be:
Since two negatives multiply to give a positive, so, we have:
*see attachment for the diagram
Answer/Step-by-step explanation:
1. Antonio's statement is correct because the sum of measure of the minor intercepted arc DE and the angle formed by tangents CE and CD outside the circle equal 180°.
According to the theorem. Therefore, the statement is correct.
2. To find the measure of <A, which is a central angle of the circle, find the value of x. Then find the measure of the intercepted arc.
According to the central angle theorem, the measure of a central angle equal the intercepted minor arc.
Therefore, the measure of the intercepted minor arc DE = m<A.
Step 1: find the value of x using the equation gotten in question 1.
Combine like terms
Step 2: find the measure of the minor intercepted arc DE, by substituting x = 25 into 5x - 2.
measure of arc DE = 5x - 2
= 5(25) - 2 = 125 - 2
measure of arc DE = 123°
Step 3: find the measure of centra angle A.
m<A = intercepted arc DE (central angle theorem)
m<A = 123°
