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3 years ago

What is the period of the sinusoidal fynction below? f(x) = 2 cos(3x – 360) + 3

Mathematics

1 answer:

dexar [7]3 years ago

4 0

Answer:

Here you go! I have a graph for your answer!

Step-by-step explanation:

The Xmin is -10

The Xmax is 10

The Ymin is -10

Ans the Ymax is 10

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If segment LN is congruent to segment NP and ∠1 ≅ ∠2, prove that ∠NLO ≅ ∠NPM:

scoundrel [369]

The missing reason to complete Hector's proof is
Corresponding Parts of Congruent Triangles Are Congruent
It's been established in the previous statement that triangle LNO and triangle PNM are congruent by the AAS Postulate.
The proof
Corresponding Parts of Congruent Triangles Are Congruent
is comprehensive.

4 0

3 years ago

Read 2 more answers

The coordinates of polygon ABCD are A(-4,-1), B(-2,3), C(2,2), and D(4,-3). Use these coordinates to complete the sentences belo

oee [108]

Answer:

The perimeter of polygon ABCD, to the nearest thousandth units is

22.227 units

The perimeter of polygon ABCD', to the nearest thousandth, would be 20.980 units

The area of polygon ABCD' is 19.5 units²

Step-by-step explanation:

The coordinates forming the polygon are

A (-4,-1), B(-2,3), C(2,2), and D(4,-3)

The perimeter then is given by the sum of the length of the sides as follows;

Length of line between two X and Y points distance, xi and yj apart is

length XY = $\sqrt{x^2+y^2}$

Therefore, the length between points AB is

length AB = $\sqrt{(-4 - (-2))^2+(-1-3)^2}$

= $\sqrt{(-4 +2)^2+(-4)^2} = \sqrt{-2^2+-4^2} = \sqrt{20}$ = 4.472 units

Similarly, length BC is given by

Length BC = $\sqrt{(-4)^2+1^2} = \sqrt{17}$ = 4.123 units

Length CD = $\sqrt{(-2)^2+5^2} = \sqrt{29}$ = 5.385 units

Length DA = $\sqrt{(8)^2+(-2)^2} = \sqrt{68}$ = 8.246 units

The perimeter is equal to;

length AB + Length BC + Length CD + Length DA

= 4.472 + 4.123 + 5.385 + 8.246 = 22.227 units

If the point D is moved up 2 units and left 1 unit we have

D' = x-1, y+2 where x and y are the coordinates of point D

D(4, -3) → D'((4-1), (-3+2)) = D'(3, -1)

The length D'A = $\sqrt{(7)^2+(0)^2} = \sqrt{49}$ =7 units

The perimeter of polygon ABCD'

length AB + Length BC + Length CD + Length D'A

= 4.472 + 4.123 + 5.385 + 7 = 20.980 units.

The area is given by the determinant of the 3 by 3 matrix using Cramer's Rule as follows

$S_{\bigtriangleup}$ = $(\frac{1}{2})|x_1y_2+x_2y_3+x_3y_1-x_1y_3-x_2y_1-x_3y_2|$

= $(\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|$

Triangle ABC we have

A(-4,-1)

B(-2,3)

C(2,2)

$S_{{\bigtriangleup}ABC}$ = $(\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|$

$=(\frac{1}{2})|(-4)(3-2)+(-2)(2-(-1)) +2((-1)-3)|$

= $=(\frac{1}{2})|-4-6 -8|= 9 units^2$

Triangle ACD'

A(-4,-1)

C(2,2)

D'(3, -1)

$S_{{\bigtriangleup}ACD'}$ = $(\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|$

$=(\frac{1}{2})|(-4)(2+1)+(2)(-1+1) +3((-1)-2)| = \frac{21}{2}$ = 10.5 units²

Area of polygon = $S_{{\bigtriangleup}ABCD'}$ = $S_{{\bigtriangleup}ABC}$ + $S_{{\bigtriangleup}ACD'}$ = (9 + 10.5) units²

Area of polygon ABCD' = 19.5 units².

7 0

2 years ago

What’s the correct answer for this question?

Helen [10]

Answer:

( -1 , 1 )

Step-by-step explanation:

(x1,y1) = (5,9)

(x2,y2) = (-7,-7)

=(-7+5/2 , -7+9/2)

= (-1,1)

3 0

3 years ago

Math Glass Worksheet (A lot of points)

Ray Of Light [21]

Answer:

You can chose 3 in 5 :o

Step-by-step explanation:

3 0

2 years ago

Given the same triangle from part C, if line segment AB measures 12 inches and line segment BC measures 5 inches what is the mea

exis [7]

Answer:

4.615 in

Step-by-step explanation:

Triangle ABC and ABD are similar because they have two corresponding congruent triangles that is right angle and ∠A. Triangle ABC and BCD are similar because they have two corresponding congruent triangles that is right angle and ∠C. Therefore Triangle ABC, ABD and BCD are similar. Since they are similar, then their sides are proportional in length.

In triangle ABC, using Pythagoras theorem:

AC² = AB² + BC²

AC² = 12² + 5²

AC² = 144 + 25 = 169

AC² = 169

AC = √169 = 13 in

Using similar triangle for ΔABC and ΔABD:

$\frac{AC}{AB}= \frac{BC}{BD} \\\\\frac{13}{12}=\frac{5}{BD}\\\\BD=\frac{12*5}{13}\\ BD=4.615\ in$

5 0

2 years ago