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Pachacha [2.7K]
3 years ago
8

A bike store sells scooters at a 54% markup. If the store bought each scooter for $29.25, what is the resale price to the neares

t dollar
Mathematics
1 answer:
7nadin3 [17]3 years ago
5 0

The purchasing price of the store = $29.25.

They want to resale it at 54% markup of the purchasing price.

54% of 29.25 = 0.54 × 29.25.

On multiplying 0.54 and 29.25, we get 15.795.

Resale price = The purchasing price + Markup

                      = 29.25 + 15.795.

On adding 29.25 and 15.795, we get 45.045.

We can round it to 45 to the nearest dollar.

<h3>Therefore, the resale price to the nearest dollar is $45.</h3>
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The ratio to this problem will have to be 15 to 54
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A horizontal trough is 16 m long, and its end are isosceles trapezoids with an altitude of 4 m, a lower base of 4 m, and an uppe
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Answer:

0.28cm/min

Step-by-step explanation:

Given the horizontal trough whose ends are isosceles trapezoid  

Volume of the Trough =Base Area X Height

=Area of the Trapezoid X Height of the Trough (H)

The length of the base of the trough is constant but as water leaves the trough, the length of the top of the trough at any height h is 4+2x (See the Diagram)

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Volume=\frac{1}{2} (4+4+2x)h X 16

=8h(8+2x)

V=64h+16hx

We are not given a value for x, however we can express x in terms of h from Figure 3 using Similar Triangles

x/h=1/4

4x=h

x=h/4

Substituting x=h/4 into the Volume, V

V=64h+16h(\frac{h}{4})

V=64h+4h^2\\\frac{dV}{dt}= 64\frac{dh}{dt}+8h \frac{dh}{dt}

h=3m,

dV/dt=25cm/min=0.25 m/min

0.25= (64+8*3) \frac{dh}{dt}\\0.25=88\frac{dh}{dt}\\\frac{dh}{dt}=\frac{0.25}{88}

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The rate is the water being drawn from the trough is 0.28cm/min.

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4 years ago
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Is 0.304 meters less than 1 meter
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Answer:

yes!

Step-by-step explanation:

because it is 0.

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Hope this makes sense! If you have further questions, let me know!

- profparis

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Answer:

75.40 feet

Step-by-step explanation:

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Hope this helped! :)

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