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3 years ago

Genus/ace/expert's PLEASE HELP

Mathematics

2 answers:

Vilka [71]3 years ago

7 0

David cuts his one roll into 1/8s, which means that he will have 8 cookies at the end.

Jake cuts his roll into 1/7s, which means his will have 7 cookies at the end (however, they would be a bit larger)

So your answer is: David will have the most cookies, and he will have 1 more cookie

hope this helps

Vsevolod [243]3 years ago

6 0

Hey there!

David: the cookie cutter rolls into 1/8 - he will have a total of 8 cookies.

Jake: the cookie cutter rolls into 1/7 - he will have a total of 7 cookies.

The number 8 is bigger than 7 . . .

David will have more cookies thank Jake.

8 - 7 = 1

He will have only 1 more cookie than Jake.

Hope this helps you.
Have a great day!

You might be interested in

Y= 2x +2

Airida [17]

Answer:

The system has one solution, at a single point of intersection.

Step-by-step explanation:

I'm going to assume that g and y are the same thing here, on a normal xy-coordinate plane. If there is actually a third dimension, 'g', then I am probably wrong, and I apologize.

For a system of 2 linear equations, a 'solution' is a point of intersection for the two lines.

If the two lines are parallel, they will have no intersection. These two equations are in the form y = mx + b, where m is the slope. If their slopes are the same, then the lines are parallel. The first equation has a slope of 2. The second equation has a slope of 6. 2 ≠ 6, obviously. They are are not parallel, so there is at least one solution (intersection)

If two equations are 'equivalent', then they represent the same exact line and you cannot find a unique solution to the system because there is no single point where they intersect. They intersect at all points, so there are an infinite number of solutions. Two equations in the same format (like point-slope) will be equivalent if you see that one is just a multiple of the other. That is not the case here. They are not equivalent, so there are not an infinite number of solutions.

For the intersection of two lines in a plane, that intersection is no point, 1 point, or infinite points.

We have ruled out no point and we have ruled out infinite points.

There must be a solution of one point where the two lines intersect.

That would be consistent with answers B and E as shown in your Brainly question.

4 0

3 years ago

Read 2 more answers

What is the answer please.... need help

mina [271]

Answer:

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

$f\left(x\right)=x^3-6x^2+3x+10$

As the highest power of the x-variable is 3 with the leading coefficients of 1.

So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

$f\left(x\right)=x^3-6x^2+3x+10$

$0=x^3-6x^2+3x+10$ ∵ $f(x)=0$

$Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

$\left(x+1\right)\left(x-2\right)\left(x-5\right)=0$

Using the zero factor principle

if $ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0$

$x=-1,\:x=2,\:x=5$

Therefore, the zeros of the function are:

$x=-1,\:x=2,\:x=5$

$f\left(x\right)=x^3-6x^2+3x+10$ is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.

8 0

3 years ago

A community bike ride offers 5.7 mile ride

Lubov Fominskaja [6]

5.7 mile ride on the community bike ride

7 0

3 years ago

I need hlep wite my homwok i am 7 years old whayt is 2x2

monitta

Answer:

Step-by-step explanation: