Question

Assume the readings on thermometers are normally distributed with a mean of 0degreesC and a standard deviation of 1.00degreesC. Find the probability that a randomly selected thermometer reads between negative 1.52 and negative 0.81 and draw a sketch of the region.

Answer 1

Answer:

Step-by-step explanation:

Given : The readings on thermometers are normally distributed with

Mean : $\mu=\ 0$

Standard deviation : $\sigma= 1$

The formula to calculate the z-score :-

$z=\dfrac{x-\mu}{\sigma}$

For x = -1.52

$z=\dfrac{-1.52-0}{1}=-1.52$

For x = -0.81

$z=\dfrac{-0.81-0}{1}=-0.81$

The p-value = $P(-1.52$

$0.2089701-0.0642555=0.1447146\approx0.1447$

Hence, the probability that a randomly selected thermometer reads between negative 1.52 and negative 0.81 = 0.1447