1) Store the cells DNA
2) Control cell division and cell growth
Answer: hydrolysis of intermediate palmitoyl Co A ,with loss of labeled CoA.before reaching the matrix gives the answer
Explanation:
This is because when the labeled Coenzyme A of the Plamitate combines as Palmitoy-CoA with oxaloacetate to form intermediate (palmitoyl-CoA )in Citric Acid cycle:
CoA is hydrolysed with loss of the labelled CoA which returns to the cystosol. Therefore, the labelled CoA does not reach the matrix of the mitochondrial,but returns to the Cystosol.
Consequently, the CoA in the Cystosol will be labelled in palmitoylCoA and the one in the matrix of the liver mitochondrial will be non radioactive(,will not labelled).
Answer:
<h2>e) 3/4
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Explanation:
As given;
Black (B) is dominant over red (b), so B is dominant over b.
Solid (S) is dominant over spotted color(s), so S is dominant over s.
Offspring of BBss and bbss individuals are:
Gametes of parent BBss are Bs, Bs and gamete of bbss are bs, bs
offspring are : all Bbss
Cross between these offspring is; Bbss×Bbss
Gametes of parent Bbss are: Bs and bs as given that the genes are linked.
Bs, bs × Bb, bs
Offspring are = BBss, Bbss, Bbss, bbss
Black spotted (B_ss) = 3/4
Answer:
Oxygen and Glucose
Explanation:
One glucose molecule is produced, and six oxygen molecules are produced.
