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emmainna [20.7K]

4 years ago

12

Is △XWY ≅ △ZWY by HL?

2 answers:

Alex_Xolod [135]4 years ago

7 0

Then the triangles are congruent

jekas [21]4 years ago

6 0

Yes these are congruent by HL
if the hypotenuse and a leg of one right triangle are congruent to the hypotenuse and a leg of a second right triangle, then the triangles are congruent

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Determine the value of c that makes the function f(x y) = c/x-y/ a joint discrete probability density function for x=2,0,2 and y

UkoKoshka [18]

Given: The given function is

$f(x,y)=c(x-y)$

To find: Here we need to find the value of c for which f(x,y) will be a joint

discrete probability density function.

Solution:

Now, to find c we have,

$\int\limits^3_{-2} \,\int\limits^2_0 {f(x,y)} \, dx dy\\=\int\limits^3_{-2} \,\int\limits^2_0 {c(x-y)} \, dx dy\\\\=\int\limits^3_{-2} \,[2c-2cy]dy\\=10c-5c\\=5c\\The integral should be1.\\So, 5c=1\\$

∴ $c=\frac{1}{5}$

Therefore, the required value of c is 1/5.

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3 years ago

Completely simplify spare root of 24x^6

satela [25.4K]

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6 0

3 years ago

Are √2−√5 real numbers?

IrinaVladis [17]

Answer:

√2 and √5 and their difference are all real numbers

Step-by-step explanation:

In looks like you want to know if the difference ...

$\sqrt{2}-\sqrt{5}$

is a real number.

The square root of a non-negative number is a real number. The sum or difference of real numbers is a real number.

The sum you have indicated is a real number, approximately ...

√2 -√5 ≈ 1.4142 -2.2361 ≈ -0.8219

4 0

3 years ago

Read 2 more answers

Simply the expression <br><img src="https://tex.z-dn.net/?f=%283%20-%202%20%5Csqrt%7Bk%20%7D%29%5E%7B2%20%7D%20" id="TexFormula1

Liula [17]

9-4 then square root of k to the 2nd power

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3 years ago

A bouncy ball is dropped such that the height of its first bounce is 2.75 feet and each successive bounce is 80% of the previous

Allushta [10]

Answer:

0.3 feet

Step-by-step explanation:

2.75(0.8)^x

in which x is the number of bounces after the firts bouce

bouce 12 would mean x=11

2.75(0.8)^11 = 0.2

7 0

3 years ago