Question

write the slope intercept form of the equation of the line with a slope of -2/5 that passes through 15, -9/2​

Answer 1

Answer:

The equation of line in slop-intercept form  is y = $\dfrac{-2x}{5}$ + $\dfrac{3}{2}$

Step-by-step explanation:

Given as :

The slope of the a line = m = $\dfrac{-2}{5}$

The line is passes through points $x_1 , y_1$ = 15 , $\dfrac{- 9}{2}$

According to question

Equation of line in slope - intercept form

y - $y_1$ = m × ( x - $x_1$ )

Or, y - ($\dfrac{- 9}{2}$ ) =  $\dfrac{-2}{5}$ × ( x - 15 )

Or, y  - ($\dfrac{- 9}{2}$ ) =  $\dfrac{-2}{5}$ ×  x  - ( $\dfrac{-2}{5}$ ) × 15

Or, y  - ($\dfrac{- 9}{2}$ ) =  $\dfrac{-2}{5}$ ×  x  + 6

Or, y =   $\dfrac{-2}{5}$ ×  x  + 6 - $\dfrac{9}{2}$

Or, y =   $\dfrac{-2}{5}$ ×  x  + $\dfrac{12-9}{2}$

Or, y = $\dfrac{-2}{5}$ ×  x + $\dfrac{3}{2}$

So, The equation of line in slop-intercept form  y = $\dfrac{-2}{5}$ ×  x + $\dfrac{3}{2}$

Hence, The equation of line in slop-intercept form  is y = $\dfrac{-2x}{5}$ + $\dfrac{3}{2}$  Answer