Let the smaller number be x and the larger number be y.
We can calculate this by using simultaneous equation, aka listing 2 equations out.
From given,
X + y = 43
Let this be equation no. 1
X + 19 = y
Let this number be equation 2.
We can do simultaneous equations either by substitute method or elimination. In this case I'm using substitute.
We can already obtain the value of y (in terms of x) in euqation no. 2, so all we gonna do is to put y into equation 1.
X + x + 19 = 43
Solve this by algebra.
2x = 43 - 19
X = 12
Now we know the exact value of x
Now substitute x = 12 into equation no. 2
12 + 19 = y
Y = 31
So the answer is 12 and 31
Answer:
x = 2
Step-by-step explanation:
x ≠ 0
x ≠ - 2
x ≠ - 1
x = 2
Answer:
6<em>i</em>
Step-by-step explanation:
sqrt(-121) - sqrt(-25)
11<em>i</em> - 5<em>i</em>
<u>6</u><u><em>i</em></u>
