Answer:
<u>There are:</u>
- 6 red balls - R
- 5 black balls - B
- Total number = 11 balls
<h3>A. Without replacement</h3>
i. <u>Two blacks </u>
ii. <u>The first is black</u>
or, alternatively
- P(BR or BB) = 5/11*6/10 + 2/11 = 3/11 + 2/11 = 5/11
iii. <u>Both are of same colour</u>
- P(BB or RR) = 2/11 + 6/11*5/10 = 2/11 + 3/11 = 5/11
<h3>B. With replacement</h3>
i. <u>Two blacks </u>
- P(BB) = 5/11*5/11 = 25/121
ii. <u>The first is black</u>
or alternatively
- P(BR or BB) = 5/11*6/11 + 25/121 = 30/121 + 25/121 = 55/121 = 5/11
iii. <u>Both are of same colour</u>
- P(BB or RR) = 5/11*5/11 + 6/11*6/11 = 25/121 + 36/121 = 61/121
How many times does 5 go into 29? It can go into it 5 times which equals 25. Now what's 29 - 25? 4 is the answer then you see how many times can 5 go into 4, well it can't so then you bring the number 0 to make it 40. Now how many times can 5 go into 40? It can go into 40 eight times since 8x5=40 so the answer is 58
Step-by-step explanation:
log 25 + log 8 = log (25 × 8) = log 200
log 200 - log 2 = log (200 ÷ 2) = log 100
logarithm base 10 of 100 is 2.
21 is the answer.You distribute 6 into the parentheses and you substitute 3 for x so 6(3-1)+9= f(x)=18-6+9 you add all the like terms and the answer is 21