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Arada [10]
3 years ago
5

Simplify p squared - 9 over p squared + p - 6​

Mathematics
1 answer:
masya89 [10]3 years ago
5 0

Answer:

=

p−3/ p−2

Step-by-step explanation:

p2−9/ p2+p−6

=

p2−9/ p2+p−6

=

(p+3)(p−3) /(p−2)(p+3)

=

p−3 /p−2

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Which of the following values are in the range of the function graphed below
expeople1 [14]

Answer:

Range of the given function = -4

Step-by-step explanation:

Range is the set of output values.

In a graph, the set of x-values of the function is know as domain and the set of y-values of the function is known as range.

In the graph red line represents the function.

From the given graph it is clear that the function is defined from x=-1 to x=4.

For each value of x the y-value is -4.

Hence, the range of the function is -4.

4 0
3 years ago
Which set Paris does not show y as a function of x?​
Alex17521 [72]

Answer:

c

Step-by-step explanation:

the x coordinations can not repeat as it does in option c so c is the answer

3 0
3 years ago
A flat screen television measures diagonally 40 inches and 24 inches in length. What
Akimi4 [234]
The width should be 32 inches.
5 0
2 years ago
Evaluate: 5-3 xwhen x=-7 Substitute-7 for x.
Mice21 [21]
The answer for this question is 26
7 0
3 years ago
Suppose that you are given a bag containing n unbiased coins. You are told that n-1 of these coins are normal, with heads on one
gladu [14]

Answer:

The (conditional) probability that the coin you chose is the fake coin is 2/(1 + n)

Step-by-step explanation:

Given

Total unbiased coin = n

Normal coins =n - 1

Fake = 1

The (conditional) probability that the coin you chose is the fake coin is represented by

P(Fake | Head)

And it's calculated as follows;

P(Fake | Head) = P(Fake, Head) ÷ P(Head) ----- (1)

Where P(Fake, Head) = P(Fake) * P(Head | Fake)

P(Fake) = 1/n --- because only one is fake

P(Head | Fake) = n/n because all coins (including the fake) have head

So, P(Fake, Head) = P(Fake) * P(Head | Fake) becomes

P(Fake, Head) = 1/n * n/n

P(Fake, Head) = 1/n

P(Head) is calculated by

P(Fake) * P(Head | Fake) + P(Normal) * P(Head | Normal)

P(Fake) * P(Head | Fake) = P(Fake, Head) = 1/n (as calculated above)

P(Normal) * P(Head | Normal) = ½ * (n - 1)/n ----- considering that the coin also has a tail with equal probability as that of the head.

Going back to (1)

P(Fake | Head) = P(Fake, Head) ÷ P(Head) becomes

P(Fake | Head) = (1/n) ÷ ((1/n) + (½(n-1)/n))

= (1/n) ÷ ((1/n) + (½(n-1)/n))

= (1/n) ÷ (1/n + (n - 1)/2n)

= (1/n) ÷ (2 + n - 1)/(2n)

= (1/n) ÷ (1 + n)/(2n)

= (1/n) * (2n)/(1 + n)

= 2/(1 + n)

Hence, the (conditional) probability that the coin you chose is the fake coin is 2/(1 + n)

5 0
3 years ago
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