Question

A cruise line ship left Port A and traveled 90 miles due west and then 400 miles due north. At this point, the ship docked at Port B What is the shortest distance between Port A and Port B?

Answer 1

Answer:

410 Miles

Step-by-step explanation:

Please refer to the photo attached. (Apologies for the legitimately terrible drawing)

The Shortest Distance between any 2 points is the distance thats connects the 2 points directly.

In this case, we can use Pythgoras's Theorem to find AB which is the shortest distance between A and B.

By Pythagoras's Theorem,

${c}^{2} = {a}^{2} + {b}^{2} \\ {ab}^{2} = {ac}^{2} + {cb}^{2} \\ {ab}^{2} = {90}^{2} + {400}^{2} \\ab = \sqrt{ {90}^{2} + {400}^{2} } \\ = 410 \: miles$