Answer:
no solutions
Step-by-step explanation:
-2(11-12x)=-4(1-6x)
Distribute
-22 +24x = -4 +24x
Subtract 24x from each side
-22 +24x-24x = -4 +24x-24x
-22 = -4
This is never true, so there are no solutions
Answer:
MY RANDOM ANSWER : my answer is 3
Step-by-step explanation:
The probablitiy of that is 9
Answer:
1) first two (A & B)
2. -1,533
Step-by-step explanation:
Sum to infinity is finite when
-1 < r < 1
Option 1: r = -¼
Option 2: r = 27/81 = ⅓
Option 3: r = 3/2
Option 4: r = 17.75/7.1 = 2.5
a = -3
r = -6/-3 = 2
S9 = -3 × (2⁹ - 1)/(2 - 1)
= -1533
Let X be the number of defective transistors. Let p be the probability that defective transistor.
P(defective transistor) = 0.04
P(non defective ) = 1- 0.04 = 0.96
A random sample of size 30 is tested for defects and we want to find probability of no defective transistor
P(No defective transistor) = P(X= 0)
Here X follows binomial distribution with parameters n=30 and p=0.04
The Binomial probability function with parameters n and p is
P(X=x) =
P(X=0) =
Using n=30 and p=0.04
P(X=0) =
P(X=0) = 1*1*(0.96)^30
P(X=0) = 0.2938
The probability that there are no defective transistors in the sample is 0.2938