Question

WILL GIVE BRAINLIEST!!!! smiddle" class="latex-formula">($x^{2}$-5x)=$log_{2}$(6x+12)
2 is the base in both logs
$x^{2}$-5x is the argument in the first log
6x+12 is the argument in second log

FIND THE DOMAIN AND THE SOLUTION TO X

Answer 1

Ps: just starting on algebra, so might not be right.

Find the domain by finding where the equation is defined.

Interval Notation:

(−2,0)∪(5,∞)

Set-Builder Notation:

{x|−2<x<0,x>5}

Solve for x

For two functions to be equal, the arguments of each must be equal.

x=12,−1

I hope this isn't wrong and if it is, sorry...