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tigry1 [53]
3 years ago
10

WILL GIVE BRAINLIEST!!!!

smiddle" class="latex-formula">(x^{2}-5x)=log_{2}(6x+12)
2 is the base in both logs
x^{2}-5x is the argument in the first log
6x+12 is the argument in second log

FIND THE DOMAIN AND THE SOLUTION TO X
Mathematics
1 answer:
balu736 [363]3 years ago
4 0

Ps: just starting on algebra, so might not be right.

Find the domain by finding where the equation is defined.

Interval Notation:

(−2,0)∪(5,∞)

Set-Builder Notation:

{x|−2<x<0,x>5}

Solve for x

For two functions to be equal, the arguments of each must be equal.

x=12,−1

I hope this isn't wrong and if it is, sorry...

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Separate The Digits Into Pairs.

Step-by-step explanation:

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3 years ago
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Tracy McKinney is a disc jockey at radio station WMMM. Her annual salary is $52,750. What is her monthly salary?
attashe74 [19]
Okay, so since her annual salary is <span>$52,750 (the amount she gets a year, all twelve months combined) you're trying to find how much she gets monthly. That would mean we would have to divide her annual salary by 12 to find her monthly salary.

</span>$52,750 ÷ 12 = 4,395.8333333333333
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5 0
3 years ago
Solve 6/7=y−3/7. I really need help.
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Pretty sure that it is 9/7.

3 0
3 years ago
Solve for x: 3/3x + 1/x+4 = 10/7x
Mekhanik [1.2K]
Given,

3/3x + 1/(x + 4) = 10/7x

1/x + 1/(x+4) = 10/7x

Because the first term on LHS has 'x' in the denominator and the second term in the LHS has '(x + 4)' in the denominator. So to get a common denominator, multiply and divide the first term with '(x + 4)' and the second term with 'x' as shown below

{(1/x)(x + 4)/(x + 4)} + {(1/(x + 4))(x/x)} = 10/7x

{(1(x + 4))/(x(x + 4))} + {(1x)/(x(x + 4))} = 10/7x

Now the common denominator for both terms is (x(x + 4)); so combining the numerators, we get,

{1(x + 4) + 1x} / {x(x + 4)} = 10/7x

(x + 4 + 1x) / (x(x + 4)) = 10/7x

(2x + 4) / (x(x + 4)) = 10/7x

In order to have the same denominator for both LHS and RHS, multiply and divide the LHS by '7' and the RHS by '(x + 4)'

{(2x+4) / (x(x + 4))} (7 / 7) = (10 / 7x) {(x + 4) / (x + 4)}

(14x + 28) / (7x(x + 4)) = (10x + 40) / (7x(x + 4))

Now both LHS and RHS have the same denominator. These can be cancelled. 

∴14x + 28 = 10x + 40
14x - 10x = 40 - 28
4x = 12
x = 12/4

∴x = 3



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