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Olenka [21]
3 years ago
5

3) The algebraic process you use to isolate a variable in order to find what values, numbers, etc. will make an equation true. Y

ou _ _ _ _ _ the equation.
Mathematics
1 answer:
vekshin13 years ago
5 0

Answer:

  You <u>solve</u> the equation.

Step-by-step explanation:

The process of finding variable values that make the equation true is called <em>solving</em> the equation.

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HELP! ASAP! Am I correct!?!?
LenKa [72]
It isn't because, it isn't consistent, and it doesn't follow any of the other answer choices. :)

3 0
3 years ago
Find the value of the trigonometric ratio, tan X.
MariettaO [177]

Answer:

A. 24/7

<u>What are sine, cosine, and tangent?</u>

SOH - CAH - TOA

sine = opposite/hypotenuse

cosine = adjacent/hypotenuse

tangent = opposite/adjacent (that is not hypotenuse)

Step-by-step explanation:

tanX = ZY/XY = 48/14 = 24/7

5 0
3 years ago
Read 2 more answers
The multiplicative inverse of (-4)⁻² is (4)⁻². True False
timofeeve [1]

Answer: false

Step-by-step explanation:

The exponents would have to have a different sign from each other (positive or negative), not the integer.

3 0
3 years ago
Please help me, thank you
Pavel [41]

Answer:

the answer is -3. Your welcome

4 0
2 years ago
The position, x, of an object is given by the equation x = A + Bt +Ct2, where t refers to time. What are the dimensions of A, B,
Serjik [45]

Answer: Dimensions of A are of length [L]

Dimensions of B are of LT^{-1}

Dimensions of C are of LT^{-2}

Step-by-step explanation:

The given equation is

x(t)=A+Bt+Ct^{2}

Since the dimension on the L.H.S of the equation is [L] , each of the terms on the right hand side should also have dimension of length[L] to be dimensionally valid

Thus

Dimensions of A = [L]

Dimensions of Bt = [L]

Bt=[L]\\\\[B][T]=[L]\\\\\therefore [B]=LT^{-1}

Similarly

Dimensions of Ct^{}2 = [L]

Ct^{2}=[L]\\\\[C][T]^{2}=[L]\\\\\therefore [C]=LT^{-2}

4 0
3 years ago
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