63. it's a cube so all you have to do is find the surface area of one side and multiply it by 6 (or you can use the actual formula)
side length^2= 8^2=64
64*6=384cm^2
Download photo math and put the problem into it it will solve it
Answer:
![\boxed {\boxed {\sf x \approx 1.9}}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Cboxed%20%7B%5Csf%20x%20%5Capprox%201.9%7D%7D)
Step-by-step explanation:
We are asked to find x, a missing side in a triangle.
This is a right triangle because there is a small square in the corner representing a 90 degree or right angle. Therefore, we can use right triangle trigonometry. The three main functions are:
- sinθ= opposite/hypotenuse
- cosθ= adjacent/hypotenuse
- tanθ= opposite/adjacent
Examine the triangle. We will use angle S, measuring 54 degrees, for theta. Side QR, measuring x, is <u>opposite</u> angle S. Side QS, measuring 2.3, is the <u>hypotenuse</u> because it is opposite the right angle. Since we have the opposite and hypotenuse, we will use sine.
![sin \theta = \frac {opposite}{hypotenuse}](https://tex.z-dn.net/?f=sin%20%5Ctheta%20%3D%20%5Cfrac%20%7Bopposite%7D%7Bhypotenuse%7D)
- θ= 54
- opposite= x
- hypotenuse = 2.3
![sin (54)= \frac{ x}{2.3}](https://tex.z-dn.net/?f=sin%20%2854%29%3D%20%5Cfrac%7B%20x%7D%7B2.3%7D)
We are solving for x, so we must isolate the variable. It is being divided by 2.3 The inverse operation of division is multiplication, so we multiply both sides by 2.3
![2.3* sin (54)= \frac{x}{2.3}*2.3](https://tex.z-dn.net/?f=2.3%2A%20sin%20%2854%29%3D%20%5Cfrac%7Bx%7D%7B2.3%7D%2A2.3)
![2.3* sin (54)=x](https://tex.z-dn.net/?f=2.3%2A%20sin%20%2854%29%3Dx)
![2.3*0.8090169944=x](https://tex.z-dn.net/?f=2.3%2A0.8090169944%3Dx)
![1.860739087 =x](https://tex.z-dn.net/?f=1.860739087%20%3Dx)
Round to the nearest tenth. The 6 in the hundredth place to the right tells us to round the 8 up to a 9.
![1.9 \approx x](https://tex.z-dn.net/?f=1.9%20%5Capprox%20x)
x is approximately <u>1.9</u>