Answer:
The range of T is a subspace of W.
Step-by-step explanation:
we have T:V→W
This is a linear transformation from V to W
we are required to prove that the range of T is a subspace of W
0 is a vector in range , u and v are two vectors in range T
T = T(V) = {T(v)║v∈V}
{w∈W≡v∈V such that T(w) = V}
T(0) = T(0ⁿ)
0 is Zero in V
0ⁿ is zero vector in W
T(V) is not an empty subset of W
w₁, w₂ ∈ T(v)
(v₁, v₂ ∈V)
from here we have that
T(v₁) = w₁
T(v₂) = w₂
t(v₁) + t(v₂) = w₁+w₂
v₁,v₂∈V
v₁+v₂∈V
with a scalar ∝
T(∝v) = ∝T(v)
such that
T(∝v) ∈T(v)
so we have that T(v) is a subspace of W. The range of T is a subspace of W.
Answer:
15% & 3/20
Step-by-step explanation:
convert decimals to % by multiplying by 100
.15 * 100 = 15%
15/100
simplify
3/20
Answer: the length of the base is 15 kilometers.
Step-by-step explanation:
formula : Area of parrallelogram = Length of base x height
Given: Area of parallelogram = 300 square kilometers
height = 20 kilometers
Substituting values in the formula , we get
300 = Length of base x 20
Length of base = 
= 15 kilometers
Hence, the length of the base is 15 kilometers.
Answer:
Step-by-step explanation:
1) Use the FOIL method: (a+b)(c+d)=ac+ad+bc+bd.
2) Collect like terms.
3) Simplify.
Therefor, the answer is, 10x^3 - 26x^2 - 12x.
