Answer: C) 
Step-by-step explanation:
Since, the graph of an inverse trigonometric function will pass through the point
,
If this point satisfies the function,
For the function 
If x = 1

Thus,
is not satisfying function
,
⇒ The graph of
is not passing through the point 
For the function 
If x = 1

Thus,
is not satisfying function
,
⇒ The graph of
is not passing through the point 
For the function 
If x = 1

Thus,
is satisfying function
,
⇒ The graph of
is passing through the point
.
For the function 
If x = 1

Thus,
is not satisfying function
,
⇒ The graph of
is not passing through the point
.
Hence, Option C is correct.