Answer:
The height of the triangle is 7cm and the base is 16cm
Step-by-step explanation:
First of all we have to know the formula to calculate area of a triangle
a = area = 56
b = base
h = heigth
a = (b * h)/2
we replace the known values and we make 2 equations
56cm² = (b * h)/2
b = h + 9cm
we replace b by (h + 9cm) in the first equation
56cm² = (h + 9cm * h)/2
56cm² * 2 = h² + 9h
0 = h² + 9h - 112cm²
we use bhaskara formula:
(-b (±) √
(b² - 4ac) ) / 2a
we replace with the known values
h = (-9 (±) √
(9² - 4*1*(-112) ) ) / 2*1
h = (-9 (±) √
(81 + 448) ) ) / 2
h = (-9 (±) √529) /2
h = (-9 (±) 23)/2
h1 = (-9 + 23) / 2
h1 = 14 / 2
h1 = 7
h2 = (-9 - 23) / 2
h2 = -32 / 2
h2 = -16
The height of the triangle is 7cm and the base is 16cm
7/8times16/1 gives 112/8, which is 14.
you multiply both numerators over both denominators.
Answer:
1
Explanation:
−((10)(2)−(2)(8)+(5)(−1))
= −(20−(2)(8)+(5)(−1))
= −(20−16+(5)(−1))
= −(4+(5)(−1))
= −(4+−5)
= −(−1)
= 1
- Mordancy.
