Question

Monica is mixing some custom colored paint for her house. The color she wants requires 3/4 ounces of blue dye and 2/3 of an ounce of pink dye mixed with each gallon of white paint base. How much dye is needed to mix 8 gallons of paint?
A. 11 5/7
B. 11 2/3
C. 11 1/3
D. 11 2/3

Answer 1

Amount of blue dye mixed with one gallon of white paint=$\frac{3}{4}$

Amount needed for 8 gallons = $\frac{3}{4}\times8=6$ ounce

Amount of pink dye mixed with one gallon of white paint=$\frac{2}{3}$

Amount needed for 8 gallons = $\frac{2}{3}\times8= \frac{16}{3}$ ounces

So, total dye required =$6+\frac{16}{3}=\frac{18+16}{3}=\frac{34}{3}$

or

$11\frac{1}{3}$ ounces.

Hence, option C is correct.