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3 years ago

9

I need your help badly. I get confused with recursive

1 answer:

WINSTONCH [101]3 years ago

7 0

Check the picture below.

the first one is simply a serie, using the previous term - 3 times the one after it.

the second one is just an arithmetic sequence, where you add the previous term plus the ordinal position.

the third one is also an arithmetic sequence, simply adding the previous term with 1.4.

recall that an arithmetic sequence is adding up, a geometric sequence is multiplying about.

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What are two numbers that add to make 36 with one of the numbers be exactly twice the other

Tema [17]

To solve, set an equation:
First Number: x
Second Number: 2x

x+2x=36
3x=36
divide both sides by 3
x=13

First Number: (x) 12
Second Number: (2x) 24

Answers: 12 and 24

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3 years ago

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Let f(x) = x^2 + 6x.

rusak2 [61]

Answer:

(A) The slope of secant line is 18.

(B) The slope of secant line is h+16.

Step-by-step explanation:

(A)

The given function is

$f(x)=x^2+6x$

At x=3,

$f(3)=(3)^2+6(3)=27$

At x=9,

$f(9)=(9)^2+6(9)=135$

The secant line joining (3,27) and (9,135). So, the slope of secant line is

$m=\dfrac{y_2-y_1}{x_2-x_1}$

$m=\dfrac{135-27}{9-3}=18$

The slope of secant line is 18.

(B)

The given function is

$f(x)=x^2+6x$

At x=5,

$f(5)=(5)^2+6(5)=55$

At x=5+h,

$f(5+h)=(5+h)^2+6(5+h)=h^2 + 16 h + 55$

The secant line joining (5,55) and $(5+h,h^2 + 16 h + 55)$ . So, the slope of secant line is

$m=\dfrac{h^2 + 16 h + 55-55}{5+h-5}$

$m=\dfrac{h^2 + 16 h }{h}$

$m=h+16$

The slope of secant line is h+16.

4 0

4 years ago

Let (8,−3) be a point on the terminal side of θ. Find the exact values of cosθ, cscθ, and tanθ.

denis23 [38]

Answer:

$\text{Cos}\theta=\frac{\text{Adjacent side}}{\text{Hypotenuse}}=\frac{x}{R}=\frac{8}{\sqrt{73}}$

$\text{Csc}\theta=-\frac{\sqrt{73}}{3}$

$\text{tan}\theta =\frac{\text{Opposite side}}{\text{Adjacent side}}=\frac{y}{x}=\frac{-3}{8}$

Step-by-step explanation:

From the picture attached,

(8, -3) is a point on the terminal side of angle θ.

Therefore, distance 'R' from the origin will be,

R = $\sqrt{x^{2}+y^{2}}$

R = $\sqrt{8^{2}+(-3)^2}$

= $\sqrt{64+9}$

= $\sqrt{73}$

Therefore, Cosθ = $\frac{\text{Adjacent side}}{\text{Hypotenuse}}=\frac{x}{R}=\frac{8}{\sqrt{73}}$

Sinθ = $\frac{\text{Opposite side}}{\text{Hypotenuse}}=\frac{y}{R}=\frac{-3}{\sqrt{73} }$

tanθ = $\frac{\text{Opposite side}}{\text{Adjacent side}}=\frac{y}{x}=\frac{-3}{8}$

Cscθ = $\frac{1}{\text{Sin}\theta}=\frac{R}{y}=-\frac{\sqrt{73}}{3}$

6 0

4 years ago

Simplify.<br> (3x2 + 2x + 7x3) + (10x2 + 6x + 9)

schepotkina [342]

Answer:

7 x 3 + 13 x 2 + 8 x + 9

Step-by-step explanation:

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4 years ago