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Pavel [41]
3 years ago
14

This is rlly hard i need help both pls

Mathematics
2 answers:
mart [117]3 years ago
4 0

Answer:

length times hight times whith

kirill [66]3 years ago
3 0

Answer:

Area = width×length

Step-by-step explanation:

i.hope this helps

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Point D What is the slope of the graph of 6x + 12y = 7? A. 1/2 B. -1/2 C. 2 D. -2
Dima020 [189]
6x + 12y = 7

12y = -6x + 7

y = -6/12 + 7

y = -1/2 + 7

the slope of the equation is -1/2
8 0
3 years ago
Which is an equation of the line with a slope of 2/3 passing through the point (4,-1)?
Bond [772]

Answer:

y=2/3x-11/3

Step-by-step explanation:

to find the y intercept, you can input your values into the equation:

b=y1−m⋅x1

When you do that, you get:

b=−1−(2/3)⋅(4)=−11/3

When you convert that equation into y=mx+b form, you get:

y=2/3x-11/3

Please mark Brainliest ;)

3 0
2 years ago
find the factors of each number. Write the common factor ( CF ) and then state the greatest common factor ( GCF) .
Reptile [31]

Given:

Two numbers are 12 and 21

To find:

The factors of 12 and 21, then find the common factor and the greatest common factor.

Solution:

Two numbers are 12 and 21. The prime factors of these two numbers are

12=2\times 2\times 3

21=3\times 7

From the above factorization, it is clear that the factor 3 is common in both. So,

Common factor (CF) = 3

Only 3 is common in factorization of both. So,

Greatest common factor (GCF) = 3

Therefore, the common factor is 3 and the greatest common factor is also 3.

6 0
3 years ago
AB is perpendicular to CD. If the slope of AB is 2/5, what is the slope of CD?​
alekssr [168]

Given a slope m, the slope m' of a line perpendicular to m is the opposite of the inverse of m

In other words:

mm' = -1 \iff m' = -\dfrac{1}{m}

So, the slope of CD is -5/2.

4 0
3 years ago
Anya saw the following equation and said she can tell this is also true far any value of x. 20(x+2)+31=4(5x+10)+31​
andre [41]

Answer:

x=0

This can be solved by reasoning.

And confirmed by substituting 0 into the expression.

6 0
2 years ago
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