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Kisachek [45]
3 years ago
8

The desktops of computers running the same OS all look the same

Computers and Technology
1 answer:
Ksju [112]3 years ago
5 0

NEIN

A computer's looks do not matter on its operating system.

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In order to be able to listen to your music, a sound card converts digital data to analog sound waves you can hear. The output signal is then connected to a headphone or set of speakers. You can also use a sound card to record audio with a microphone
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What does UDP stand for?
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User Datagram Protocol
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3 years ago
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Write a program that records high-score data for a fictitious game. the program will ask the user to enter five names, and five
Harman [31]

Scores.cpp

#include <iostream>

#include <string>

using namespace std;

void initializeArrays(string names[], int scores[], int size);

void sortData(string names[], int scores[], int size);

void displayData(const string names[], const int scores[], int size);

int main()

{

   string names[5];

   int scores[5];

   //reading names and scores

   initializeArrays(names, scores, 5);

   //sorting the lists based on score.

   sortData(names, scores, 5);

   //displaying the contents of both arrays

   displayData(names, scores, 5);

 

  return 0;

}

void initializeArrays(string names[], int scores[], int size){

   for(int i=0; i<size; i++){

       cout<<"Enter the name for score #"<<(i+1)<<": ";

       cin >> names[i];

       cout<<"Enter the score for score #"<<(i+1)<<": ";

       cin >> scores[i];

       }

}

void sortData(string names[], int scores[], int size){

   

       int temp = 0;

       string tempStr = "";

       

       for(int i=0; i < size; i++){

               for(int j=1; j < (size-i); j++){

                      //checking max score and sorting based on it.

                       if(scores[j-1]< scores[j]){

                               //swap the elements!

                           //swapping scores

                               temp = scores[j-1];

                               scores[j-1] = scores[j];

                               scores[j]=temp;

                               

                               //swapping names

                               tempStr = names[j-1];

                               names[j-1] = names[j];

                               names[j]=tempStr;

                       }

                       

               }

       }

}

void displayData(const string names[], const int scores[], int size){

   cout<<"Top Scorers:"<<endl;

       //printing the elements up to the size of both arrays.

       for(int i=0; i<size; i++){

           cout<<names[i]<<": "<<scores[i]<<endl;

       }

}

3 0
3 years ago
Suppose for the worst case, given input size n: Algorithm 1 performs f(n) = n2 + n/2 steps Algorithm 2 performs f(n) = 12n + 500
melomori [17]

Answer:

29

Explanation:

for n=28:

--------------

Algorithm 1 performs f(n) = n2 + n/2 = 28*28 + 28/2 = 798

Algorithm 2 performs f(n) = 12*28 + 500 = 836

for n=29

--------------

Algorithm 1 performs f(n) = n2 + n/2 = 29*29 + 29/2 = 855.5

Algorithm 2 performs f(n) = 12*29 + 500 = 848

so, for n=29, algorithm 2 will be faster than algorithm 1

6 0
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The answer is creating and layout and template style

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