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earnstyle [38]
3 years ago
11

Please help please help

Mathematics
1 answer:
stiks02 [169]3 years ago
6 0

I believe the answer should be 102. It has been a long time since I have done one of these but I believe that if you times the outside angle by 2 then it is the angle if the point were to be in the center.

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Factor x^4 + xy^3 + x^3 + y^3. Hint, first factor a monomial. Please explain why!!!
almond37 [142]

Pull an x from the first two terms

x(x^3 + y^3) + (x^3 + y^3)   Now x^3 + y^3 is a common factor.

(x^3 + y^3)*(x + 1) That should be far enough. It can be factored further by factoring (x^3 + y^3) but there is no point because you can't do anything after that. But in case you want to know how x^3 + y^3 factors

(x^3 + y^3) = (x + y)(x^2 - xy + y^2)

Which means you could write original polynomial as

(x + y)(x^2 - xy + y^2)(x + 1)

Part B

You factored the x out of xy^3 so that you would have a common factor (x^3 + y^3) to pull out as a common factor for the whole polynomial.

3 0
3 years ago
Angie wants to bake cookies for a bake sale. The recipe says, "for every one cup of butter use three cups of flour." What does "
lisabon 2012 [21]

Answer:

Step-by-step explanation:

The term "for every" is a ratio indicator, meaning that every single time you use or do one thing then you must also do or use another thing. In this scenario, it is stating that every single time that you add a single cup of butter to the cookie recipe then you must also add three cups of flower to that recipe. This ratio always maintains its proportions meaning that if you add 2 cups of butter to the recipe you would need to add six cups of flower.

4 0
3 years ago
PLEASE HELP ME . I’m taking the quiz now
loris [4]

Answer: (12,2480),(−1,−380)

Step-by-step explanation:

4 0
3 years ago
What two numbers you can add together to give you 9 and also multiply the two numbers to give 14
vivado [14]
Factors of 14: 7 and 2

7 + 2 = 9
5 0
3 years ago
plz help i need helpplz help i need helpplz help i need helpplz help i need helpplz help i need helpplz help i need helpplz help
Volgvan

Answer:

the answer should be 9

Step-by-step explanation:

(256 * 3^{-5} * 6^{0} )^{-2} * (\frac{3^{-2}}{2^{3}} )^{4} * 2^{28}

(256*\frac{1}{3^{5}} *6^{0})^{-2}*(\frac{3^{-2}}{2^{3}})^{4}*2^{28}

(256*\frac{1}{243} *6^{0})^{-2}*(\frac{3^{-2}}{2^{3}})^{4}*2^{28}

(\frac{256}{243} *6^{0})^{-2}*(\frac{3^{-2}}{2^{3}})^{4}*2^{28}

(\frac{256}{243})^{-2}*(\frac{3^{-2}}{2^{3}})^{4}*2^{28}

(\frac{243}{256})^{2}*(\frac{3^{-2}}{2^{3}})^{4}*2^{28}

\frac{59049}{65536}*(\frac{1}{2^{3}*3^{2}})^{4}*2^{28}

\frac{59049}{65536}*(\frac{1}{8*9})^{4}*2^{28}

\frac{59049}{65536}*(\frac{1}{72})^{4}*2^{28}

\frac{59049}{65536}*\frac{1}{26873856}*2^{28}

\frac{9}{65536}*\frac{1}{4096}*2^{28}

\frac{9}{65536*4096}*2^{28}

\frac{9}{268435456}*268435456

9

6 0
3 years ago
Read 2 more answers
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