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Dominik [7]
3 years ago
12

Please help me ASAP!! I have no idea.

Mathematics
2 answers:
alex41 [277]3 years ago
7 0
4 unknowns with 1 equation. there are too many possibilities to this solution to have it accurate
Julli [10]3 years ago
6 0
Multiply by 3 in both sides to get rid of the equation, then subtract "r" and "t" in both sides of the equation. 

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gabriel put 6000 in a 2 year CD paying 4% interest, compounded monthly. After 2 years , he withdrew all his money. what was the
shutvik [7]

amount after 2 years   = 6000(1 + (0.04/12))^24  = 6498.86
7 0
3 years ago
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Which measures of central tendency would be affected if the outlier 11 was added to the following set 27,20,34,37,21,42,39
MrRa [10]

Answer:

Median will not be affected by the outlier.

Step-by-step explanation:

With the outlier, the mean will be dragged way down. The median will likely be about the same. Mean is non-resistant to outliers, median is resistant.

Hope this helps!

5 0
3 years ago
Some electronic devices are better used than new: the failure rate is higher when they are new than when they are six months old
Reptile [31]
Given that half of the personal music players sold by a particular brand have a flaw. If the player has the​ flaw, it dies in the first six months. If it does not have this​ flaw, then only 20​% fail in the first six months.
Let A be the event that it fails in I 6 months
B1 = it has a flaw
B2 = it does not have a flaw
B1 and B2 are mutually exclusive and exhaustive
the chances that it has this​ flaw
=The probability that it has the flaw is

7 0
3 years ago
Find c.<br> Round to the nearest tenth:<br> 2 cm<br> 15°<br> 105
Anit [1.1K]

Answer:

0.5cm

Step-by-step explanation:

Using the sine rule

4 0
3 years ago
Read 2 more answers
Prove sin^2 theta-sin^2 theta is sin tetha sin 3 theta<br><br>how to prove..pls help!! thanksss
Artemon [7]
Simply you can substitute theta=45 degrees (or any angle,not zero) in left hand side and right hand side.

or 

using a^2 - b^2 =(a+b)(a-b)

= sin(2x+x)sin(2x-x)
= sin 3x sin x
3 0
3 years ago
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