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Softa [21]
4 years ago
11

Help with #3 math question?

Mathematics
1 answer:
Marizza181 [45]4 years ago
5 0
I'm pretty sure it's the second answer. When you put 0 in for a, you get -3, 1 in for a you get 1, 2 in for a and you get 5 as an answer, and so on
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I NEED HELP WILL GIVE BRAINLIEST!! PLEASE HELP ME ASAP!!!!
GenaCL600 [577]

Answer:

A. The length of the second leg is 8.5 inches

B. The length of the three-dimensional diagonal is 9.9 inches

Step-by-step explanation:

Let us revise the relation between the hypotenuse and the two legs of a right triangle

(hypotenuse)² = (vertical leg)² + (horizontal leg)²

∵ The length of the rectangular box = 8 inches

∵ The width of the rectangular box = 3 inches

∵ The height of the rectangular box = 5 inches

∵ Length and width are perpendicular to each other

∴ The Δ whose legs are 3 and 8 is a right triangle

In the right Δ whose legs are 3 and 8

∵ (hypotenuse)² = (3)² + (8)²

∴ (hypotenuse)² = 9 + 64

∴ (hypotenuse)² = 73

- Take √  for both sides

∴ hypotenuse = \sqrt{73} = 8.544003745

- Round it to the nearest tenth of one inch

∴ hypotenuse = 8.5 inches

A.

The 3-dimensional diagonal is the hypotenuse of a right triangle whose legs are the vertical edge and the hypotenuse of the right triangle whose legs are 3 and 8

∵ The hypotenuse of the right triangle whose legs are 3 and

   8 is 8.5 inches

∴ The length of the second leg is 8.5 inches

B.

In the right triangle whose hypotenuse is the 3-dimensional diagonal and legs are the vertical edge , the hypotenuse of the right triangle whose legs are 3 and 8

∵ (3-dimensional diagonal)² = (5)² + (73)²

∴ (3-dimensional diagonal)² = 25 + 73

∴ (3-dimensional diagonal)² = 98

- Take √ for both sides

∴ 3-dimensional diagonal = \sqrt{98} = 9.899494937

- Round it to the nearest tenth of an inch

∴ 3-dimensional diagonal = 9.9 inches

∴ The length of the three-dimensional diagonal is 9.9 inches

<em>V.I.N: you can find the length of the  three-dimensional diagonal by using this rule → </em>d=\sqrt{l^{2}+w^{2}+h^{2}}<em> </em>

3 0
4 years ago
2. In one year, there were a total of 13,332 kidney transplants
Sloan [31]

Answer:

i think it is 37

Step-by-step explanation:

8 0
4 years ago
How to solve : 16=2t + 0.25 t``squar​
Marysya12 [62]

Answer:

The solutions of the equation are t = 4(√5 + 1) or 4(√5 - 1).

Step-by-step explanation:

We have to solve the given quadratic equation of single variable t.

The equation is 16 = 2t + 0.25t²

⇒ 0.25t² + 2t - 16 = 0

⇒ 25t² + 200t - 1600 = 0 {Multiplying both sides with 100}

⇒ 25t² + 200t + 400 - 400 - 1600 = 0

⇒ (5t + 20)² - 2000 = 0

⇒ (5t + 20)² - (20√5)² = 0

⇒ (5t + 20 + 20√5)(5t + 20 - 20√5) = 0

So, (5t + 20 + 20√5) = 0 or, (5t + 20 - 20√5) = 0

⇒ (t + 4 + 4√5) = 0 or, (t + 4 - 4√5) = 0

⇒ t = - 4(1 + √5) or, t = 4(√5 - 1) (Answer)

8 0
3 years ago
What else would need to be congruent to show that AABC = APQR by SSS?
Svetradugi [14.3K]

Answer:

B, because that's the side that wasn't given

Step-by-step explanation:

7 0
3 years ago
A certain drug dosage calls for 460 mg per kg per day and is divided into four doses (1 every 6 hours). If a person weighs 229 p
Setler [38]

Answer:

11.95 g / 6 hours  

Step-by-step explanation:

drug dosage = 460 mg per kg per day

to be administered every 6 hours to a person who weighs 229 pounds

1 pound = 0.453592 kg

229 pounds = 229 × 1 pound = 229 × 0.453592 kg = 103.873 kg

dosage of drug needed for 103.873 kg

460 mg is to 1 kg per day

103.873 kg = 103.873 × 460 mg per 1 kg per day = 47781.58 mg per 103.873 kg per day

number of 6 hours in a day = 24 hours ÷ 6 hours = 4 times per day

dosage needed per 6 hours

47781.58 ÷ 4 = 11945.395 mg for every 6 hours = 11.95 g / 6 hours  

3 0
4 years ago
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