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ss7ja [257]
3 years ago
11

How do I do the first one .

Mathematics
1 answer:
Lilit [14]3 years ago
7 0

Answer:

186 cookies per table

Step-by-step explanation:

744 divide by 4

for part b

186 divided by 3 = 62

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Is number square root of 2,500 rational or irrational
ddd [48]
Rational

\sqrt{2500 }  = 50
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3 years ago
The average amount of time that students use computers at a university computer center is 36 minutes with a standard deviation o
frosja888 [35]

Answer:

2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 36, \sigma = 5

The first step to solve this question is finding the proportion of students which use the computer more than 40 minutes, which is 1 subtracted by the pvalue of Z when X = 40. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{40 - 36}{5}

Z = 0.8

Z = 0.8 has a pvalue of 0.7881.

1 - 0.7881 = 0.2119

So 21.19% of the students use the computer for longer than 40 minutes.

Out of 10000

0.2119*10000 = 2119

2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.

8 0
3 years ago
Will give The BRAINLIEST
Alborosie

Answer:

A - (-6,-2)

B - (2,-2)

C - (2,-7)

4 0
3 years ago
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5 0
3 years ago
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A team is being formed that includes eight different people. There are eight different positions on the teams. How many differen
abruzzese [7]

Answer:

40320 different ways

Step-by-step explanation:

That problem is a permutation one

We have eight people to occupy  one position in a team, without any constraint at all

So

Total number of events   = P(8)

P (8)  =  8!

P (8)  =  8*7*6*5*4*3*2*1

P (8)  =  40320 different ways

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3 years ago
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