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myrzilka [38]
3 years ago
14

I need help!!!!!!!!!!!!

Mathematics
1 answer:
Crazy boy [7]3 years ago
6 0

Answer:

13.53................

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Use the continuous compound interest formula to find the indicated value. A=90,000; P=65,452; r=9.1%; t=? t=years (Do not round
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\bf \qquad \textit{Simple Interest Earned}\\\\
A=Pe^{rt}\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &90,000\\
P=\textit{original amount}\to& \$65,452\\
r=rate\to 9.1\%\to \frac{9.1}{100}\to &0.091\\
t=years
\end{cases}

\bf 90000=65452e^{0.091t}\implies \cfrac{90000}{65452}=e^{0.091t}\implies \cfrac{22500}{16363}=e^{0.091t}
\\\\\\
\textit{taking \underline{ln} to both sides}\qquad ln\left( \cfrac{22500}{16363} \right)=ln\left( e^{0.091t} \right)
\\\\\\
ln\left( \cfrac{22500}{16363} \right)=0.091t\implies 
\cfrac{ln\left( \frac{22500}{16363} \right)}{0.091}=t
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