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algol [13]
3 years ago
15

Please help me with this!!

Mathematics
1 answer:
Naddik [55]3 years ago
3 0

Step-by-step explanation:

To find the y-coordinate points we need to evaluate the function for all the x values in the table. In other words, we need to replace x with each value in our given function and simplify.

- For x = 0

f(x)=(x-2)^2-5

f(0)=(0-2)^2-5

f(0)=(-2)^2-5

f(0)=4-5

f(x)=-1

Since x=0 and y=-1, our first point is (0, -1)

- For x = 1

f(x)=(x-2)^2-5

f(1)=(1-2)^2-5

f(1)=(-1)^2-5

f(1)=1-5

f(x)=-4

Our second point is (1, -4)

- For x = 2

f(x)=(x-2)^2-5

f(2)=(2-2)^2-5

f(2)=(0)^2-5

f(x)=-5

Our third point is (2, -5)

- For x = 3

f(x)=(x-2)^2-5

f(3)=(3-2)^2-5

f(3)=(1)^2-5

f(3)=1-5

f(x)=-4

Our fourth point is (3, -4)

- For x = 4

f(x)=(x-2)^2-5

f(4)=(4-2)^2-5

f(4)=(2)^2-5

f(4)=4-5

f(x)=-1

Our fifth point is (4, -1)

Now we just need to plot each point in our coordinate plane and join them with the parabola as you can see in the attached picture.

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During a blizzard it snowed 5 and 8/10in after a week the sun had melted 3 and 1/2 inches of snow how many inches of snow is lef
WITCHER [35]

2\frac{3}{10} inches of snow is left

<em><u>Solution:</u></em>

Given that,

From given,

Original\ amount\ of\ snow = 5\frac{8}{10}\ inches = \frac{10 \times 5 + 8}{10} = \frac{58}{10}\ inches

Sun\ melted = 3\frac{1}{2}\ inches = \frac{2 \times 3 + 1}{2} = \frac{7}{2}\ inches

<em><u>how many inches of snow is left</u></em>

Snow left = original amount of snow - sun melted

Snow\ left = \frac{58}{10} - \frac{7}{2}\\\\Snow\ left = \frac{58}{10} - \frac{7 \times 5}{2 \times 5}\\\\Snow\ left = \frac{58}{10} - \frac{35}{10}\\\\Snow\ left = \frac{58 - 35}{10}\\\\Snow\ left = \frac{23}{10}\\\\\In\ mixed\ fractions\\\\Snow\ left = 2\frac{3}{10}

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3 0
3 years ago
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9514 1404 393

Answer:

  5) 729, an=3^n, a[1]=3; a[n]=3·a[n-1]

  6) 1792, an=7(4^(n-1)), a[1]=7; a[n]=4·a[n-1]

Step-by-step explanation:

The next term of a geometric sequence is the last term multiplied by the common ratio. (This is the basis of the recursive formula.)

The Explicit Rule is ...

  a_n=a_1\cdot r^{n-1}

for first term a₁ and common ratio r.

The Recursive Rule is ...

  a[1] = a₁

  a[n] = r·a[n-1]

__

5. First term is a₁ = 3; common ratio is r = 9/3 = 3.

Next term: 243×3 = 729

Explicit rule: an = 3·3^(n-1) = 3^n

Recursive rule: a[1] = 3; a[n] = 3·a[n-1]

__

6. First term is a₁ = 7; common ratio is r = 28/7 = 4.

Next term: 448×4 = 1792

Explicit rule: an = 7·4^(n-1)

Recursive rule: a[1] = 7; a[n] = 4·a[n-1]

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