All categories

3 years ago

What is the volume of a cylinder with a base radius of 2 and height of 9?

Mathematics

1 answer:

il63 [147K]3 years ago

6 0

Answer:

v ≈ 113.09

Step-by-step explanation:

v = πr^2*h

v = π*2^2*9

v = π*4*9

v = π*36

v = 113.097335529

hope this helps :)

You might be interested in

Simplify the rational expression x^4 y^2/xy^7.

sammy [17]

Answer: $x^3y^9$

Step-by-step explanation:

Reformatting the input :

Changes made to your input should not affect the solution:

(1): Dot was discarded near "7.".

STEP 1:

Simplify $\frac{y^2}{x}$

The equation at the end of step 1:

$((x^4)*\frac{y^2}{x} )*y^7$

Multiplying exponential expressions:

2.1 $y^2$ multiplied by $y^7$ $=y^(2+7)=y^9$

Final result is $x^3y^9$

8 0

1 year ago

This is due in a bit and im having a bit of trouble, any solutions?

valina [46]

Answer:

I believe that those triangles are not similar

Step-by-step explanation:

5 is 1.666 of 3

20/3=6.667

1.666 does not equal 6.667

if I did that correctly, they are not similar

Hope this helps!

5 0

2 years ago

Math - Use unit conversion factor to convert the units.

nlexa [21]

Answer: 240 minutes, 20 cups, 4000 pounds

Step-by-step explanation:

Use the following conversions:

1 hour = 60 minutes

2 cups = 1 pint

2 pints = 1 quart

1 ton = 2000 pounds

$4\ hours\times \dfrac{60\ minutes}{1\ hour}=\large\boxed{240\ minutes}\\\\\\\\5\ quarts \times \dfrac{2\ pints}{1\ quart}\times \dfrac{2\ cups}{1\ pint}=\large\boxed{20\ cups}\\\\\\\\2\ tons\times \dfrac{2000\ pounds}{1\ ton}=\large\boxed{4000\ pounds}$

8 0

2 years ago

A field trip is planned which is 10 2/9 miles from school. A wheel of the school bus is punctured after 5 3/7. How many miles ar

lisabon 2012 [21]

4 50/63 is the answer

6 0

2 years ago

An asteroid follows a hyperbolic path defined by the equation 16x2 − 9y2 = 576. If one of its foci is the sun's position, the mi

amid [387]

The minimum distance between the asteroid and the sun is 10 - 6 =4

The given hyperbolic path defined as
divide both the sides by 576,

The general equation of

hyperbola is written as
;

Compare with above mention equation
Here

The distance between the asteroid and the sun is seen by figure -1
or
⇒c =10

The minimum distance between the asteroid and the sun is 10 -6 =4

4 0

3 years ago