The mean of the distribution given is 0.569.
Given some distribution like under:
x p(x)
0 0.650
1 0.216
2 0.087
3 0.026
4 0.014
5 0.009
We have to find the mean of the distribution.
Mean is the sum of numbers divided by the numbers which are taken into consideration. It is also known as average.
Mean=sum/n
To find the mean of distribution we have to find sum of x*p(x)
∑xp(x)=0*0.650+1*0.216+2*0.0087+3*0.026+4*0.014+5*0.009
=0+0.216+0.174+0.078+0.056+0.045
=0.569
Hence the mean of the distribution given in the question is 0.569.
Learn more about mean at brainly.com/question/1136789
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Distribution in the given question is wrong and the right question is as the right distribution is as under:
x p(x)
0 0.650
1 0.216
2 0.087
3 0.026
4 0.014
5 0.009
Answer:
carlos will have one brownie left over.
Step-by-step explanation:
im smart
Answer:
We can conclude that on this case we have identical processes but excersise 17 use another way to present the probability distribution and as we can see the expected value can be viewed as a dot product of two vectors with one vector containing the outcomes and the other the probabilities for each possible outcome.
Step-by-step explanation:
Assuming this previous info:
Exercise 17. Suppose that we convert the table on the previous page displaying the discrete distribution for the number of heads occurring when two coins are flipped to two vectors.
Let vector
