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baherus [9]
4 years ago
10

Cal Johnson compares his checkbook register, cancelled checks, and bank statement which shows a balance of $325. He finds two ou

tstanding checks for $53.58 and $20.24. There is also an outstanding deposit of $62. What is his adjusted balance?
$189.17
$313.18
$336.82
$460.82
Mathematics
2 answers:
V125BC [204]4 years ago
8 0

the answer is $313.18

Cerrena [4.2K]4 years ago
8 0

Answer:

$313.18.

Step-by-step explanation:

Given : Cal Johnson has an account balance of $325.

          He finds two outstanding checks for amount $53.58 and $20.24.

           There is also an outstanding deposit of $62

Solution : Cal Johnson has an account balance of $325.

Since he has outstanding checks of amount $53.58 and $20.24.

When his outstanding checks amount gets deducted from the account then the new account balance will be :

$325 - $53.58 - $20.24 = $251.18

So, after the deduction of outstanding check amounts new account balance is $251.18.

Now, there is also an outstanding deposit of amount $62

So, after the deposition of that amount new account balance will be :$251.18 + $62 = $313.18.

Thus the adjusted account balance is $313.18.


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. If her allowance had stayed the same, $9.00 a month, how many carnival tickets could she bu
jarptica [38.1K]

Answer:

a) number of tickets she could buy in a month with her allowance in 2008 = 4 tickets

b) number of tickets she could buy in a month with the same allowance in 2012 = 2 tickets

c) $5, an increase of 55.56%

d) $2, a 100% increase.

e) Hallie was able to buy more tickets in 2008 than in 2012.

f) $16

Step-by-step explanation:

The complete question is presented in the attached image to this answer.

a) Halie's allowance monthly = $9

Price of a ticket in 2008 = $2

number of tickets she could buy in a month with her allowance = (9/2) = 4.5 = 4 tickets (since there are no half tickets)

b) Halie's allowance monthly = $9

Price of a ticket in 2012 = $4

number of tickets she could buy in a month with her allowance = (9/4) = 2.25 = 2 tickets (since there are no quarter tickets)

c) In 2012, Hallie's allowance was $14.00 per month. How much did her monthly allowance increase between 2008 and 2012?

Her monthly allowance in 2008 = $9

Her monthly allowance in 2012 = $14

The increase = new allowance - old allowance = 14 - 9 = $5

In percentage terms,

% increase = 100% × (new - old)/(old)

% increase = 100% × (14 - 9)/9 = 55.56%

d) How much more did a carnival ticket cost in 2012 than it did in 2008?

Price of a ticket on 2008 = $2

Price of a ticket in 2012 = $4

Increase in price = 4 - 2 = $2

% increase = 100% × (4 - 2)/2 = 100%

e) Was Hallie able to buy more carnival tickets in 2008 or in 2012 with one month's allowance?

Hallie was able to buy more tickets in 2008 than in 2012.

f) What would Hallie's allowance need to be in 2012 in order for her to be able to buy as many carnival tickets as she could in 2008?

Hallie could buy 4 tickets in 2008.

Price of a ticket in 2012 = $4.

Price of 4 tickets in 2012 = 4 × $4 = $16

Hope this Helps!!!!

3 0
3 years ago
Match the part of the circle with the term that best describes it.​
nordsb [41]
GH: chord
M: point of tangency
MJ: diameter
J: center
MH: radius
GH: secant
6 0
3 years ago
Alisha asked 120 students what kind of pet they liked the most. Exactly 45% of the students said they liked dogs best. What was
7nadin3 [17]

Answer: 54 liked best

Step-by-step explanation: None

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3 years ago
Read 2 more answers
Reduce 7y + 2y 2 - 7 by 3 - 4y.
NARA [144]

Answer:

D. 2y^2+11y-10.

Step-by-step explanation:

Given:

We need to reduce 7y+2y^2-7 by 3-4y

Solution:

To reduce the equation means we need to subtract the one equation from other.

First we will arrange the equation n proper format we get;

2y^2+7y-7  ⇒ equation 1

Also Arranging other equation we get;

-4y+3   ⇒ equation 2

Now we will subtract equation 2 from equation 1 we get;

(2y^2+7y-7)-(-4y+3)

Now Applying distributive property for the sign we get;

2y^2+7y-7+4y-3

Now Arranging the like terms we get;

2y2+7y-+4y-7-3\\\\2y^2+11y-10

Hence the reduce form of the given equation is 2y^2+11y-10.

7 0
3 years ago
The table shows information about some children.
Sindrei [870]

Answer:

P(Age\ 12) = \frac{2}{3}

Step-by-step explanation:

Given

        Age 11    Age 12    Total  

Girls   3             5              8

Boys   1             3             4

Required

P(Age\ 12)

The number of aged 12 children is:

Age\ 12 = 5 + 3

Age\ 12 = 8

The total number of children is:

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Total = 12

So, we have:

P(Age\ 12) = \frac{Age\ 12}{Total}

P(Age\ 12) = \frac{8}{12}

Simplify

P(Age\ 12) = \frac{2}{3}

3 0
3 years ago
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