Question

A normal population has a mean u = 31 and standard deviation = 10. What proportion of the population is less than 30?​

Answer 1

The proportion of the population exists less than 30 then

(x< 30) = 0.986.

How to estimate the proportion of the population that exists less than 30?​

To estimate the z-score using the formula, z = (x - µ)/σ

Where, x be the randomly chosen values = 30

µ be the mean = 31

σ be the standard deviation = 10

Proportion of the population that exists less than 18 = P(x < 30)

Plug in the values into z = (x - µ)/σ, to get z-score.

Substitute the values in the above equation, we get

z = (30 - 31)/10

z = -1/10 = -0.1

Therefore, the value of z = - 0.1.

To learn more about proportion of the population refer to:

brainly.com/question/18403865

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