Answer:
y=-2x+7
Step-by-step explanation:
You just subtract 2x from both sides to get y alone
The answer is D, or 168.
The cheese can be any one out of 3 = 3 choices. For each of those . . .
The first topping can be any one of 8. For each of those . . .
The second topping can be any one of the remaining 7 . For each of those . . .
The third topping can be any one of the remaining 6 .
Total number of ways to assemble a pizza = (3 x 8 x 7 x 6) = 1,008 ways.
<span>BUT . . . </span>
You could choose the SAME 3 toppings in (3 x 2) = 6 different ways, and
nobody could tell the difference once they were selected. All 6 different
ways would result in the same pizza.
So, out of the 1,008 total different ways there are of choosing ingredients,
<span>there are only ( 1,008 / 6 ) = </span>168<span> different and distinct pizzas.</span>
Answer:
The sample size required is 102.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean <em>μ</em> is:
The margin of error for this interval is:
Given:
<em>σ</em> = 9.2
(1 - <em>α</em>)% = 90%
MOE = 1.5
The critical value of <em>z</em> for 90% confidence level is:
*Use a <em>z</em>-table.
Compute the value of <em>n</em> as follows:
![n=[\frac{z_{\alpha/2}\times \sigma}{MOE}]^{2}](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csigma%7D%7BMOE%7D%5D%5E%7B2%7D)
![=[\frac{1.645\times 9.2}{1.5}]^{2}\\=101.795\\\approx102](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B1.645%5Ctimes%209.2%7D%7B1.5%7D%5D%5E%7B2%7D%5C%5C%3D101.795%5C%5C%5Capprox102)
Thus, the sample size required is 102.
Answer:
The value is 14
Step-by-step explanation:
six less than (next quotient -6) the quotient of a number and two (n/2), increased by ten (+10) when n = 20.
(<u>n</u>/2)+10-6; <u>n=20</u>
<em>Substitute 20 in for n.</em>
(<u>20/2</u>)+<u>10-6</u>
<em>Divide and subtract.</em>
<u>10+4</u>
<em>Add.</em>
14
