The actual width of the room is 20 ft and the actual length of the room is 15 ft
Since on the scale, 2 in : 5 ft and the width of the room on the drawing is 8 in.
Let the actual width of the room is w.
The ratio of the drawing to actual width is 8 in : w
So, 2 in : 5 ft = 8 in : w
2 in/5 ft = 8 in/w
So, w = 8 in × 5 ft/2 in
w = 4 × 5 ft
w = 20 ft
Also, the length of the room on the drawing on the drawing is 6 in.
Let the actual length of the room is L.
The ratio of the drawing to actual length is 6 in : L
So, 2 in : 5 ft = 6 in : L
2 in/5 ft = 6 in/L
So, L = 6 in × 5 ft/2 in
L = 3 × 5 ft
L = 15 ft
So, the actual width of the room is 20 ft and the actual length of the room is 15 ft.
Learn more about scale drawing here:
brainly.com/question/25324744
Answer:
b. day 2 is the farthest from 0
The answer to your algerbra question is eight over y
Twice the difference between 5 times a number and 6 equals 18:
2(5x-6)=18
We need to solve for x:
5x - 6 = 2(difference) = 18
The difference must equal 9.
In order for the difference to equal 9, x must equal 3.
5(3) - 6 = 2(difference) = 18
Let's solve:
15 - 6 = 2(9) = 18
Therefore, in this equation, x = 3.
