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Firdavs [7]
3 years ago
9

Select the expression that is equivalent to the given polynomial.

Mathematics
1 answer:
lesantik [10]3 years ago
6 0

Observe that 16r^4 is the square of 4r^2, and 625 is the square of 25.

So, your expression is a difference of squares, and as such we can rewrite it as

16r^4-625=(4r^2+25)(4r^2-25)

Now again, 4r^2 is the square of 2r, and 25 is the square of 5. So, we have a sum and a difference of squares.

But if we think of 25 as -(5i)^2, we have again the difference of two squares, so we have

4r^2+25=(2r+5i)(2r-5i)

4r^2-25=(2r+5)(2r-5)

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Enter the simplified form of the complex fraction in the box.
Ket [755]

The problem is:

\frac{\frac{3}{x}+\frac{1}{4}}{1+\frac{3}{x}}

We now do L.C.M. of numerator and add, also do L.C.M. of denominator and add together:

\frac{\frac{12+x}{4x}}{\frac{x+3}{x}}

Dividing by a fraction is same as multiplying by its reciprocal, so we have:

\frac{12+x}{4x} * \frac{x}{x+3} \\

x cancels out, so can multiply and write:

\frac{12+x}{4} * \frac{1}{x+3} \\=\frac{12+x}{4x+12}

This is the simplified form.


ANSWER: \frac{12+x}{4x+12}

3 0
3 years ago
Y=3x + 1 for x = 1 2 3 4 5
Olegator [25]

1: 1/3

2. 1/6

3. 1/9

4. 1/12

5. 1/15

6 0
3 years ago
Can someone help me out
GalinKa [24]
Elaine's, line up your decimal and add zeros.
7 0
4 years ago
Twelve flags are evenly spaced around a running track. Ryan started running at the first flag and took 30 seconds to reach the s
aniked [119]

Answer:

Ryan takes 6n+36m -42 seconds to reach the nth flag for the mth time.

Step-by-step explanation:

It takes Ryan to run from 1st to 6th flag in 30 seconds, so it takes him

30 * 6/3 = 36 seconds to make one complete round.

or it takes 6 seconds to run from one flat to the next.

To reach the nth flag (n=1,2,3,4,5, or 6)

Ryan takes 6(n-1) seconds.

To reach it the mth times, he needs to add 36(m-1) seconds.

So time it takes Ryan to reach the nth flag for the mth time takes

6(n-1) + 36(m-1)

= 6n - 6 + 36m - 36

= 6n+36m -42 seconds

3 0
3 years ago
A group of tourists went downstream a river and are supposed to return in 3 hours. How far can the tourists travel down the rive
Olenka [21]
D=vt

So they will travel downstream and upstream the same distance.  Downstream they will travel:

d=(2+18)t1

Upstream they will travel:

u=(18-2)t2

Since d=u we can say:

20t1=16t2

We are told the trip lasts 3 hours so t1+t2=3, t2=3-t1, using this in the equation above we have:

20t1=16(3-t1)

20t1=48-16t1

36t1=48

t1=4/3 hours, and from earlier we saw that d=20t1 so:

d=20*4/3

d=80/3 miles

d=26 2/3 miles.

6 0
3 years ago
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