Let n be the number. The difference of the number and six is n-6. Then three times the difference of the number and six is 3·(n-6). This number 3·(n-6) increased by four times the number n, then
3·(n-6)=4·n.
Solve it:
3·n-3·6=4n,
3n-4n=18,
-n=18,
n=-18.
Answer: n=-18 and expression is 3·(n-6)=4·n.
Answer: The expenses of the fundraiser is $1500
Step-by-step explanation:
P(n) models the fundraiser's profit (in dollars) where n represents the number of tickets that are sold. The equation is expressed as
P(n) = 70n - 1500
A negative profit means the expenses exceeded the income from tickets. Looking at the model, for the charity organization to make profits, the product of the number of tickets sold and the cost per ticket must exceed $1500. If it is below $1500, then it is a negative profit. This means that the expenses is $1500
Answer:
C(t) = $28,000(0.811)^t (Answer A)
Step-by-step explanation:
The value of the car is decreasing. Thus, by the end of the first year of ownership, the car will have the value $28,000(1 -0.189)^1, where the "-0.189" represents DECAY instead of GROWTH.
Please use " ^ " to indicate exponentiation.
Then the desired formula is C(t) = $28,000(0.811)^t (Answer A)
Answer:
True
Step-by-step explanation:
Every input (x) has one output(y). If you were to plug in any of the x values from a point from this graph to this function(not given) you'd get one y value