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pickupchik [31]
3 years ago
10

What is the volume of the frustum? Express the answer in terms of π.

Mathematics
2 answers:
Lisa [10]3 years ago
6 0

Answer:

The volume of the frustum is: 34.8 \, \pi \,units^3

which corresponds to the third answer shown in the list of options

Step-by-step explanation:

The image can be interpreted as an original tall cone of height 6.4 plus 6.8 (13.2) that was divided into two parts by chopping the smaller upper cone, and leaving the frustum (the volume of which we need to find). So, to estimate the volume of this frustum, knowing the general formula for the volume of a cone:

Volume= \frac{1}{3} B\,h   (where B is the area of the cone's base, and h its height)

we could calculate the volume of the larger cone, and subtract from it the volume of the upper smaller one.

For the area of the cone's base, recall call also that the area of a circle of radius R is given by: \pi\,R^2, and therefore the formula for the volume of the cone can be written as:

Volume= \frac{1}{3} \pi\,R^2\,h

So, now the volume of the larger cone is:

Volume= \frac{1}{3} \pi\,R^2\,h= \frac{1}{3} \pi\,3^2\,13.2=39.6\,\pi

The volume of the smaller cone:

Volume= \frac{1}{3} \pi\,R^2\,h= \frac{1}{3} \pi\,1.5^2\,6.4=4.8\, \pi

Therefore, the difference becomes: 39.6\,\pi-4.8\,\pi=34.8\,\pi

This is the volume of the frustum: 34.8 \, \pi \,units^3

Alecsey [184]3 years ago
6 0

The answer is D

44.4π units^3

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Find the measures of angles S and T in the triangle below.
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Step-by-step explanation:

The type of triangle we’re looking at is a equilateral triangle meaning all sides and all angle measures measure the exact same thing.

With all this information, angle S and T measure 60*
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3 years ago
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dangina [55]
The answer is C -1/2.
4 0
2 years ago
The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require
grigory [225]

Answer:

142.2 meters.  

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.      

Let us find total surface area of box using surface area formula of cuboid.

\text{Total surface area of cuboid}=2(lb+bh+hl), where,

l = Length of cuboid,

b = Breadth of cuboid,

w = Width of cuboid.

\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)

\text{Total surface area of box}=2(2520+432+840)

\text{Total surface area of box}=2(3792)

\text{Total surface area of box}=7584

Therefore, the total surface area of box will be 7584 square cm.  

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}

80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2

\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=14220\text{ cm}

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}

\text{ Length of canvass}=142.20\text{ m}

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

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3 years ago
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