Hey there!
The biggest side in the set of 3 lengths needs to be lower than the sum of the two lower numbers. So 3 is not lower than 1+1. 10 is not less than 3+4. 5 is the same as 3+2. This is not possible because this makes a line. So the biggest side can’t equal the sum of the two lower sides. 10 is less than 5+9. So the answer would be the last one. 10 cm, 5 cm, 9 cm.
I hope this helps!
Answer:10x2 - 10x - 6 needs simplified first so you get 90x - 6. Also if you know X I can help you solve it just tell me what X is
Step-by-step explanation:
- m<1 = 145 | Supplementary
- m<3 = 35 | Vertical
- m<4 = 145 | Supplementary
- m<5 = 145 | (With Angle 4) If parallel then alternate interior angles congruent
- m<6 = 35 | (With Angle 5) Supplementary
- m<7 = 35 | (With Angle 6) Vertical
- m<8 = 145 | (With Angle 7) Supplementary
Hope it helps <3
(If it does, maybe brainliest :) Need one more for rank up)
<h2><u>Part A:</u></h2>
Let's denote no of seats in first row with r1 , second row with r2.....and so on.
r1=5
Since next row will have 10 additional row each time when we move to next row,
So,
r2=5+10=15
r3=15+10=25
<u>Using the terms r1,r2 and r3 , we can find explicit formula</u>
r1=5=5+0=5+0×10=5+(1-1)×10
r2=15=5+10=5+(2-1)×10
r3=25=5+20=5+(3-1)×10
<u>So for nth row,</u>
rn=5+(n-1)×10
Since 5=r1 and 10=common difference (d)
rn=r1+(n-1)d
Since 'a' is a convention term for 1st term,
<h3>
<u>⇒</u><u>rn=a+(n-1)d</u></h3>
which is an explicit formula to find no of seats in any given row.
<h2><u>Part B:</u></h2>
Using above explicit formula, we can calculate no of seats in 7th row,
r7=5+(7-1)×10
r7=5+(7-1)×10 =5+6×10
r7=5+(7-1)×10 =5+6×10 =65
which is the no of seats in 7th row.
Yes it is a function
Y=x(x-1)
X(x-1)
X to the 2nd power -1x
Hope that’s helps
