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3 years ago

Rounded to the nearest ten thounsend

1 answer:

8 0

To round the numbers, make the numbers whose last four digit are 0001 through 4999 into the next lower number that ends in 0000.
EXAMPLE 54,424 rounded to the nearest ten thousand would be 50,000.

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What’s the solution set for x? Can someone please answer and explain how they got they’re answer for 40 points.

xz_007 [3.2K]

Answer:

i think the answer is 2.I had a problem like this and i think u have to find out what both of them equal

3 0

2 years ago

99 POINTS WILL GIVE BRAINLIEST!! No fake answers!

bazaltina [42]

He has a 26% of getting a strike, which means he has a 74% chance of not getting a strike ( 100% - 26% = 74%).

Multiply the chance of not getting a strike by the number of attempts:

0.74 x 0.74 x 0.74 x 0.74 x 0.74 = 0.22

The answer is B) 0.22

The probability of making a free throw is 77%, the probability of not making one would be 23% ( 100% - 77% = 23%).

Add the probability of making the first one ( 0.77) by the probability of making the second one multiplied by the probability of missing the second one ( 0.77x 0.23)

0.77 + (0.77 x 0.23)

0.77 + 0.18 = 0.95

The answer is D) 95%

6 0

2 years ago

Read 2 more answers

Simplify the expression. 6(7n – 5m) + 8m

borishaifa [10]

6(7n – 5m) + 8m
42n - 30m + 8m
42n -22m
Answer: 42n-22m

7 0

3 years ago

Read 2 more answers

The students in Mr. Wilson's Physics class are making golf ball catapults. The

Mnenie [13.5K]

Answer:

Part a) About 48.6 feet

Part b) About 8.3 feet

Part c) The domain is $0 \leq x \leq 48.6\ ft$ and the range is $0 \leq y \leq 8.3\ ft$

Step-by-step explanation:

we have

$y=-0.014x^{2} +0.68x$

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

where

x is the ball's distance from the catapult in feet

y is the flight of the balls in feet

Part a) How far did the ball fly?

Find the x-intercepts or the roots of the quadratic equation

Remember that

The x-intercept is the value of x when the value of y is equal to zero

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-0.014x^{2} +0.68x=0$

$a=-0.014\\b=0.68\\c=0$

substitute in the formula

$x=\frac{-0.68(+/-)\sqrt{0.68^{2}-4(-0.014)(0)}} {2(-0.014)}$

$x=\frac{-0.68(+/-)0.68} {(-0.028)}$

$x=\frac{-0.68(+)0.68} {(-0.028)}=0$

$x=\frac{-0.68(-)0.68} {(-0.028)}=48.6\ ft$

therefore

The ball flew about 48.6 feet

Part b) How high above the ground did the ball fly?

Find the maximum (vertex)

$y=-0.014x^{2} +0.68x$

Find out the derivative and equate to zero

$0=-0.028x +0.68$

Solve for x

$0.028x=0.68$

$x=24.3$

<em>Alternative method</em>

To determine the x-coordinate of the vertex, find out the midpoint between the x-intercepts

$x=(0+48.6)/2=24.3\ ft$

To determine the y-coordinate of the vertex substitute the value of x in the quadratic equation and solve for y

$y=-0.014(24.3)^{2} +0.68(24.3)$

$y=8.3\ ft$

the vertex is the point (24.3,8.3)

therefore

The ball flew above the ground about 8.3 feet

Part c) What is a reasonable domain and range for this function?

we know that

A reasonable domain is the distance between the two x-intercepts

$0 \leq x \leq 48.6\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 48.6 feet

A reasonable range is all real numbers greater than or equal to zero and less than or equal to the y-coordinate of the vertex

we have the interval -----> [0,8.3]

$0 \leq y \leq 8.3\ ft$

All real numbers greater than or equal to 0 feet and less than or equal to 8.3 feet

8 0

2 years ago

what is the value of y in the solution to the following system of equations? (5 points) 2x y = −4 5x 3y = −6

TiliK225 [7]

2x+y=-4
5x+3y=-6

multiply first equaton by -5 and second by 2 then add them

-10x-5y=20
<u>10x+6y=-12 +</u>
0x+1y=8

y=8

the y value is 8

7 0

3 years ago