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Arlecino [84]
3 years ago
13

Jessica is on a the swim team. Each day she swims 8000m. Use the the fact to find how much this is in kilometers

Mathematics
2 answers:
Musya8 [376]3 years ago
7 0

Answer:

8 Kilometers

Step-by-step explanation:

1m=0.001km

   So...

8000m=8km

iVinArrow [24]3 years ago
5 0

Answer:

0.8

Step-by-step explanation:

Jessica can swim a lap in  seconds

Converting it into decimals,

Means  seconds

Means Jessica can swim a lap in 29.4 seconds

Marta can swim a lap in 28.7 seconds.

So, Martha is faster than Jessica by  seconds

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Mary wants to hang a mirror in her room. the mirror and frame must have an area of 7 square feet. the mirror is 2 feet wide and
Helen [10]

The quadratic equation use to determine the thickness of the frame, x is 4x² + 10x - 1 = 0.

The correct option is D.

<h3>What is a quadratic equation ?</h3>

A quadratic equation is an algebraic equation of the second degree in x.. The quadratic equation is written as ax2 + bx + c = 0, where x is the variable, a and b are the coefficients, and c is the constant term.

<h3>According to the given information:</h3>

Total area  = 7 square feet

and,

Total area = Length x Width

So,

7 = (2x + 3)(2x + 2)

7 = 4x2 + 4x + 6x + 6

7 = 4x2 + 10x + 6

4x2 + 10x + 6 - 7 = 0

4x2 + 10x - 1 = 0

Hence,

The quadratic equation use to determine the thickness of the frame, x is 4x² + 10x - 1 = 0.

To know more about quadratic equation visit:

brainly.com/question/1863222

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I understand that the question you are looking for is:

Mary wants to hang a mirror in her room. the mirror and frame must have an area of 7 square feet. The mirror is 2 feet wide and 3 feet long.  Square with an inner frame with height of 2 ft on the left frame and width of 3 ft on the top. Arrow on the bottom frame with an x and an arrow on the right frame with an x. Which quadratic equation can be used to determine the thickness of the frame, x?

A. x² + 14x - 2 = 0

B. 2x² + 10x - 7 = 0

C. 3x² + 12x - 7 = 0

D. 4x² + 10x - 1 = 0

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1 year ago
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Is there a picture or is that it
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Midpoint of the segment connecting the points (5,3)and (7,-2)is (6,1/2)
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Zigmanuir [339]
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