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3 years ago

Help please!!!!! Geometry

Mathematics

1 answer:

RideAnS [48]3 years ago

5 0

Answer:

Step-by-step explanation:

E gets prio rather than D & F, so E is the first letter. after that, D has more prio than F. so the answer is EDF.

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An air traffic controller spots two airplanes at the same altitude converging to a point as they fly at right angles to each oth

muminat

So.... notice the picture below

we know when y = 140 and x = 240, r = 250

so let's use the pythagorean theorem

$\bf r^2=x^2+y^2\implies 2r\cfrac{dr}{dt}=2x\cfrac{dx}{dt}+2y\cfrac{dy}{dt}\implies \cfrac{dr}{dt}=\cfrac{x\frac{dx}{dt}+y\frac{dy}{dt}}{r}
\\\\\\
\cfrac{dr}{dt}=\cfrac{240\cdot 480+70\cdot 140}{250}\implies \cfrac{dr}{dt}=500$

now... how much time does the controller have? well, say, plane "y" is going at dy/dt of 140mph, and is 70 miles away, 140 is 2*70, so it can cover those 70 miles in 1/2 hr, and when it does, it'll collide with the other,

so, the controller has that much, less than 1/2 hr

8 0

3 years ago

2/7+1/7+1/7= answer plss

Gnom [1K]

Answer:

2÷7+1÷7+1÷7 = 0.57142857142

7 0

2 years ago

Read 2 more answers

Write the square or cube for each number.

IRISSAK [1]

Answer:

1) 19³=6859

2) 16² =256

3) 15³ =3375

4) 20² =400

5) 10³ =1000

Step-by-step explanation:

using your calculator to (square = number times itself) or (cube = number times itself times itself again)

4 0

2 years ago

2. The sum of k and 10 is 48

Amiraneli [1.4K]

Answer:

k=38

Step-by-step explanation:

38+10=48

7 0

2 years ago

Find dy/dx by implicit differentiation. y cos x = 5x2 + 3y2

lbvjy [14]

Step 1:
Start by putting $\frac{d}{dx}$ in front of each term

$\frac{d}{dx}[y cos x]= \frac{d}{dx}[5x^2]+ \frac{d}{dx}[ 3y^2]$
-----------------------------------------------------------------------------------------------------------------
Step 2:

Deal with the terms in 'x' and the constant terms
$\frac{d}{dx}[ycosx]= 10x+ \frac{d}{dx} [3y^2]$
----------------------------------------------------------------------------------------------------------------
Step 3:

Use the chain rule for the terms in 'y'
$\frac{d}{dx}[ycosx]=10x+6y \frac{dy}{dx}$
--------------------------------------------------------------------------------------------------------------
Step 4:

Use the product rule on the term in 'x' and 'y'
$(y) \frac{d}{dx} cos x+(cos x) \frac{d}{dx}y =10x+6y \frac{dy}{dx}
$
$y(-siny)+(cosx) \frac{dy}{dx} =10x+6y \frac{dy}{dx}$
--------------------------------------------------------------------------------------------------------------

Step 5:

Rearrange to make $\frac{dy}{dx}$ the subject
$-y sin(y)+cos(x) \frac{dy}{dx} =10x+6y \frac{dy}{dx}$
$cos(x) \frac{dy}{dx}-6y \frac{dy}{dx}=10x+y sin(y)$
$[cos(x) - 6y] \frac{dy}{dx}=10x + y sin(y)$
$\frac{dy}{dx}= \frac{10x+ysin(y)}{cos(x)-6y}$ ⇒ Final Answer

5 0

3 years ago