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schepotkina [342]
3 years ago
11

In ΔCAB, point E is the midpoint of AC and point D is the midpoint of BC . If the measure of AB is 8 units, what is the measure

of segment ED ?
3 units

4 units

5 units


6 units
Mathematics
2 answers:
kondor19780726 [428]3 years ago
8 0

Answer:

B.) 4

Step-by-step explanation:

strojnjashka [21]3 years ago
5 0

Answer:

4 units

Step-by-step explanation:

CAB and EAD are similar triangles with sides in the ratio 2:1

ED = ½ AB

½(8)

4

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Someone help me pls
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6 0
2 years ago
What is the range of the function on the graph?
SIZIF [17.4K]

Answer: All real numbers less than or equal to 3.

Explanation: I took a test with this question and got it right.

3 0
3 years ago
I’ve been trying sooo hard to get this and i can’t, please help
Greeley [361]

Should be 37 if you use Pythagorean theorem!

7 0
3 years ago
A circle that has a center at the point (3, -2) with a radius of 6. Write an equation for the circle.
crimeas [40]

Answer:

(x – 3)^2+ (y +2)^2 = 36

Step-by-step explanation:

Given data

The formula for the equation of a circle is (x – h)2+ (y – k)2 = r^2,

where (h, k) represents the coordinates of the center of the circle

h=3

k=-2

r= 6

Substitute

(x – 3)^2+ (y – (-2))^2 = 6^2

(x – 3)^2+ (y +2)^2 = 36

Hence the expression for the equation of the circle is

(x – 3)^2+ (y +2)^2 = 36

5 0
3 years ago
Calculate the resistance of a 270-cm length of copper wire with a 0.030-cm2 cross-sectional area. ( = 1.8 · 10-6 ohm-cm) R = ___
devlian [24]

Answer:

Given:-

The length of copper wire (L) = 270 cm

Area of cross-sectional (A) = 0.030 cm^2

and specific resistance (ρ) = 1.8 \times 10^{-6} ohm-cm.

Use the formula  R=(Specific resistance*L)/A, to calculate the Resistance(R)

then, R=\frac{1.8 \times 10^{-6} \times 270}{0.030} ohm

Simplify:

R = 0.0162 ohm = 1.62\times 10^{-2} ohm

Therefore, the resistance of copper wire is,  1.62\times 10^{-2} Ω


8 0
3 years ago
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