Z=11.1i-45 re(z) and lm(z)

numbers of the wide waters Club pay $105 per summer season plus $9.50 each time they rent a boat non members must pay $14.75 eac

Ahat [919]

The member pays $9.50 to take a boat out,
plus $105 just to be a member.

Let's call ' R ' the number of rentals

   Member Cost = (9.50 times R) + 105

Non-member cost = (14.75 times R) .

You're interested in when their costs are equal,
so at that point, we can write ...

   Member cost = non-member cost

   9.5 R + 105 = 14.75 R

Subtract 9.5 R from each side: 105 = 5.25 R

Divide each side by 5.25 : 20 = R

If you're going to rent a boat less than 20 times during the
Summer season, rent them at the non-member rate.

More than 20 times in 1 Summer, you'll save money by being
a member.

This sounds a bit extreme to me. If the Summer season means
ALL of May, June, July, August, and September, then you would
need to average more than one rental every 7.65 days ... a hair
more than one a week ... in order to save any money by being a
member. I love sailboat rental, and I live just 2 miles from Lake
Michigan, but even at these prices (cheap), I would never average
a rental every week for 5 months.   So for me, there would be no
benefit in a membership ... at least not in the cost of boat rental.

========================================

Another way to do it, with more brain but less algebra:

Each time a member rents a boat, he pays (14.75 - 9.50) = 5.25
LESS than a non-member would pay to rent the same boat.
But in order to get that deal, he had to pay $105 "up front", at the
beginning of the season, before he ever rented anything.

How many times does he have to 'save' $5.25 before he makes up
for the the $105 ?

   ($105) / ($5.25) = 20 times .

8 0

4 years ago

Read 2 more answers

I NEED HELP FAST! Which of the following sets of numbers could not represent the three sides of a triangle?

olya-2409 [2.1K]

Answer:

15 27 44

Step-by-step explanation the two smaller numbers combined has to be bigger than the other number.

5 0

4 years ago

If the parent function f(x) = x^2 is fatter translated 11 units to the left, then translated 5 units down, write the resulting f

nikklg [1K]

The quadratic function given by:

$f(x)=a(x-h)^2+k, \ \ \ a\neq 0$

is in vertex form. The graph of $f$ is a parabola whose axis is the vertical line $x=h$ and whose vertex is the point $(h, k)$ . So:

To translate the graph of a function to the right, left, upward or downward we have:

$For \ a \ positive \ real \ number \ c. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:\\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ g(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ g(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{right}: \\ g(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{left}: \\ g(x)=f(x+c)$

By knowing this things, we can solve our problem as follows:

FIRST.

Translating 11 units to the left:

$g(x)=f(x+11) \\ \\ \therefore g(x)=(x+11)^2$

Then translating 5 units down:

$g(x)=f(x)-c \\ \\ \therefore g(x)=(x+11)^2-5$

Since the new function is fatter, the factor we need to multiply the term $(x+11)^2$ must be less than 1, to make the graph fatter. So, according to our options, there are two factors 1/2 and 2.