We can group the expression x³ + 4x² + 5x + 20 as (x³ + 4x²) + (5x + 20). We have factor out the common factors and have
(x³ + 4x²) + (5x + 20)
x²(x + 4) + 5(x + 4)
From this, we have x³ + 4x² + 5x + 20 = x²(x + 4) + 5(x + 4). And thus, the answer is <span>B.</span>
Answer:
the answer to what??
Step-by-step explanation:
Answer: (29.4, 32.6)
Step-by-step explanation:
From the question, we know that
Sample size (n) = 27
Sample mean (x) = $31
Sample standard deviation (s) = $3
We are to construct a 99% confidence interval interval for average amount spent on gift.
The formulae for constructing a 99% confidence interval for population mean is given as
u = x + tα/2 × s/√n...... For upper limit
u = x - tα/2 × s/√n...... For lower limit
tα/2 is the critical value for a 2 tailed test. This value of gotten from a t distribution table by checking the degree of freedom ( 27 - 1 = 26) against the level of significance ( 100% - 99% = 1%).
Hence tα/2 = 2.779
Let us substitute our parameters and solve
For lower limit
u = 31 - 2.779 × 3/√27
u = 31 - 2.779 ( 0.5773)
u = 31 - 1.6045
u = 29.4
For upper limit
u = 31 + 2.779 × 3/√27
u = 31 + 2.779 ( 0.5773)
u = 31 + 1.6045
u = 32.6
Hence the 99% confidence interval for population mean is given as 29.4, 32.6
Answer:
see below
Step-by-step explanation:
1st: x
2nd: 5x + 8
x(5x + 8) = 36
5x² + 8x = 36
5x² + 8x - 36 = 0
(x - 2)(5x + 18) = 0
(x - 2) = 0
x - 2 = 0
x = 2
1st: x = 2
2nd: 5x + 8 = 5(2) + 8 = 18
(5x + 18) = 0
5x + 18 = 0
5x = -18
x = -3.6
1st: x = -3.6
2nd: 5x + 8 = 5(-3.6) + 8 = -18 + 8 = -10
