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vazorg [7]
3 years ago
6

If m <1= 36 what is the measure of its complement?

Mathematics
1 answer:
Vlada [557]3 years ago
3 0
If A represents an angle, its complement is 90-A.

If m<1 = 36, then its complement is 90-36 (degrees), or 54 (degrees).
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Find the value of x ?!??
goldfiish [28.3K]

Answer:

x=4

Step-by-step explanation:

Pentagon's sum of interior angle is 540°

let's add all the given degrees

100+20x+16x+16+140+160-5x=540

Collect like terms

100+16+140+160+20x+16x-5x=540

416+31x=540

31x=540-416

31x=124

x=124/31

x=4```

5 0
3 years ago
Find the surface area of the sphere.
fenix001 [56]

Answer:

804 in^2

Step-by-step explanation:

The surface area of a sphere is given by A = 4πr^2, where r is the radius of the sphere.

Here, A = 4π*8^2 in^2 (must use units of measurement)

              =256π in^2, or approximately 804 in^2

4 0
3 years ago
Read 2 more answers
The port of South Louisiana, located along 54 miles of the Mississippi River between New Orleans and Baton Rouge, is the largest
Ksenya-84 [330]

Answer:

a) 0.7287

b) 0.9663

c) 0.237

d) 3.65 tons of cargo per week or more that will require the port to extend its operating hours.  

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  4.5 million tons of cargo per week

Standard Deviation, σ = 0 .82 million tons

We are given that the distribution of number of tons of cargo handled per week is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P( port handles less than 5 million tons of cargo per week)

P(x < 5)

P( x < 5) = P( z < \displaystyle\frac{5 - 4.5}{0.82}) = P(z < 0.609)

Calculation the value from standard normal z table, we have,  

P(x < 5) =0.7287= 72.87\%

b) P( port handles 3 or more million tons of cargo per week)

P(x \geq 3) = P(z \geq \displaystyle\frac{3-4.5}{0.82}) = P(z \geq −1.82926)\\\\P( z \geq −1.82926) = 1 - P(z < -1.829)

Calculating the value from the standard normal table we have,

1 - 0.0337 = 0.9663 = 96.63\%\\P( x \geq 3) = 96.63\%

c)P( port handles between 3 million and 4 million tons of cargo per week)

P(3 \leq x \leq 4) = P(\displaystyle\frac{3 - 4.5}{0.82} \leq z \leq \displaystyle\frac{4-4.5}{0.82}) = P(-1.829 \leq z \leq -0.609)\\\\= P(z \leq -0.609) - P(z < -1.829)\\= 0.271-0.034 = 0.237= 23.7\%

P(3 \leq x \leq 4) = 23.7\%

d) P(X=x) = 0.85

We have to find the value of x such that the probability is 0.85.

P(X > x)  

P( X > x) = P( z > \displaystyle\frac{x - 4.5}{0.82})=0.85  

= 1 -P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.85  

=P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.15  

Calculation the value from standard normal z table, we have,  

P( z \leq -1.036) = 0.15

\displaystyle\frac{x - 4.5}{0.82} = -1.036\\x = 3.65

Thus, 3.65 tons of cargo per week or more that will require the port to extend its operating hours.

8 0
3 years ago
Factor 16x2 + 40x + 25
scoray [572]
The answer is c to your question
3 0
3 years ago
PLEASE HELP! WILL MARK BRAINLIEST!
dedylja [7]

Answer:

at first put the value of X

after that do the equation.

Step-by-step explanation:

hope it will help you

5 0
3 years ago
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