answer -2
Step-by-step explanation:
plug 4 for n the put in a calculator hope this helps
Answer:
First term (a) =8
Common difference (d)= t2-t1
=12-8
=4
Now, sum of first 31th term (tn31) =n/2{2a+(n-1)d}
= 31/2{2×8+(31-1)4}
=31/2{16+(30×4)
=31/2(16+120)
=31/2×126
=31×63
Step-by-step explanation:
Similarly use 19 as (n) for the 19th term
Answer:
140
Step-by-step explanation:
just mutiply 35 by 4, thats h0w i g0t it anyways, h0pe this helped :)
