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3 years ago

Distribute property of 7x +7y

Mathematics

1 answer:

Vesna [10]3 years ago

6 0

It would be 7(x+y)
It’s just pulling out the common factors in each set.

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Use the MacLaurin series for f(x).

katrin [286]

y = tan^−1(x2/4) tan(y) = x2/4 sec2(y) = x/2 y′ = xcos^2(y)/2 cos^2(y) = 16x2+16 y′ = 8x/(x2+16)

let u be x2+16
du is 2x dx
dy = 4 du / u
y = 4 ln (x2 + 16)

y at x =0 = 4 ln (16) = 11.09

6 0

3 years ago

She dhb shush’s heheh she he Use n n I g me en

AVprozaik [17]

Answer:

what?

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

I wasn't in school today can someone explain how to do this

Pachacha [2.7K]

You have to multiply 7 3/4 to 9.

First, turn 7 3/4 to an improper fraction which is 31/4.
Next, you multiply 31/4 to 9/1(same thing as 9) across from each other.
Then, you get the answer 279/4(31 x 9 = 279 ;4 x 1 = 4; 279/4).
Last divide 279 to 4 and get 67.75( .75 = 3/4 ; 69 3/4).

7 0

3 years ago

You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o

Aleksandr [31]

Answer:

Therefore the circumference of the circle is $=\frac{20\pi}{4+\pi}$

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

$\Rightarrow s=\frac{10-\pi r}{2}$

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

$A=\pi r^2+ (\frac{10-\pi r}{2})^2$

$\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2$

$\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}$

$\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25$

For maximum or minimum $\frac{dA}{dr}=0$

Differentiating with respect to r

$\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi$

Again differentiating with respect to r

$\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}$ > 0

For maximum or minimum

$\frac{dA}{dr}=0$

$\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0$

$\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}$

$\Rightarrow r=\frac{10}{4+\pi}$

$\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0$

Therefore at $r=\frac{10}{4+\pi}$ , A is minimum.

Therefore the circumference of the circle is

$=2 \pi \frac{10}{4+\pi}$

$=\frac{20\pi}{4+\pi}$

4 0

3 years ago

The graph of a proportional relationship passes through (12,16) and (1,y). find y

anastassius [24]

Answer:

4/3

Step-by-step explanation:

A proportional relationship is a relationship that crosses through the origin or (0,0). This means the slope of the line can be found by subtracting the points (12,16) and (0,0) in the slope formula.

$m = \frac{y_2-y_1}{x_2-x_1} =\frac{16-0}{12-0}= \frac{16}{12}=\frac{4}{3}$

So the slope is 4/3 and must be the value between any two points on the line.

This means the function moves from (0,0) to (1, 4/3).

4 0

4 years ago