Answer:
12 pound
Step-by-step explanation:
Let 
be the weight of the package.
For Lone Star Shipping, the cost will be:
For Discount Shipping Company, the cost will be:
We hence equate these two expressions equal to each other, since the cost should be same.
The string is assumed to be massless so the tension is the sting above the 12.0 N block has the same magnitude to the horizontal tension pulling to the right of the 20.0 N block. Thus,
1.22 a = 12.0 - T (eqn 1)
and for the 20.0 N block:
2.04 a = T - 20.0 x 0.325 (using µ(k) for the coefficient of friction)
2.04 a = T - 6.5 (eqn 2)
[eqn 1] + [eqn 2] → 3.26 a = 5.5
a = 1.69 m/s²
Subs a = 1.69 into [eqn 2] → 2.04 x 1.69 = T - 6.5
T = 9.95 N
Now want the resultant force acting on the 20.0 N block:
Resultant force acting on the 20.0 N block = 9.95 - 20.0 x 0.325 = 3.45 N
<span>Units have to be consistent ... so have to convert 75.0 cm to m: </span>
75.0 cm = 75.0 cm x [1 m / 100 cm] = 0.750 m
<span>work done on the 20.0 N block = 3.45 x 0.750 = 2.59 J</span>
Answer:
∠G = 37°
∠H = 143°
Step-by-step explanation:
As we know ,
Sum of supplementary angles is 180 degrees.
Hence sum of ∠G and ∠H is also 180 degrees
∠G + ∠H = 180
Substituting the given values in above equation, we get -
∠G = (x + 4)° = (33 + 4)° = 37°
∠H = (4x + 11)° = (33*4 + 11)° = 143°
The answer is 1/5 of the students are blond girls, since 1/3 of 3/5 is 1/5.
Divide 3/5 by 3, which is 1/5.
Hope this helps!
